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NARA [144]
3 years ago
13

What is the value of 4 in the decimal 4.706

Mathematics
1 answer:
juin [17]3 years ago
6 0

Answer:

whole number

Step-by-step explanation:

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Devide 60 in the ratio of 2:3​
nevsk [136]

Answer:

Let the amounts be 2x and 3x.

Then 2x+3x=60

So, 5x=60

So, x=60/5=12

So, amounts are

2x=2*12=24

And 3x=3*12=36

Hope this helps you!

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLEASE HELP THIS IS VERY IMPORTANT I'LL GIVE YOU BRAIN THING IF ITS CORRECT!! <3 NO LINKS PLEASEE.
Nataly_w [17]

Answer and Step-By-Step Explanation:

The point shown is marked at (36,82), meaning that the panda is 36 months old and weighs 82 kilograms.  To plot the next point, just go up from 110 on the graph to 90 and mark a point.  (Sorry I tried to put an image but it was extremly blurry.)

7 0
3 years ago
Form a paragraph proof for the following. Make sure you include all the
timama [110]

Answer:

Line BD is Congruent to Line BD due to the Reflexive property. Angle Bad is congruent to angle BCD because of the third angle theorem therefore triangle ABD is congruent to triangle CBD because all angles and sides are congruent

I don't know if that will satisfy your teacher because some prefer different things but that leaves no ground to be inferred and explains everything word for word.

8 0
3 years ago
Please Help: 0.125r - 0.0625 + 0.25r = 0.25 + r
IRISSAK [1]

Answer:

r=0.5

Step-by-step explanation:

0.125r+0.25r-0.0625=0.25+r

0.375r-0.0625=0.25+r

0.375r-r=0.25+0.0625

-0.625r=0.3125

r=0.3125/0.625

r=0.5

7 0
3 years ago
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
2 years ago
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