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GuDViN [60]
2 years ago
7

Quadrilateral PQRS is dilated by a scale factor of 1/2 with point R as the center of dilation, resulting in the image P'Q'R'S'.

Which statement is true about line segment P'S'?
Mathematics
1 answer:
Pachacha [2.7K]2 years ago
3 0

The statement that is true about line segment P'S' is (c) Segment P'S' s 4 units long and lies on a different segment

<h3>How to determine the true statement?</h3>

The complete question is in the attached image

From the image, we have:

PS = 8 units

This means that:

P'S' = 1/2 * PS

So, we have:

P'S' = 1/2 * 8

Evaluate

P'S' = 4

Also, the segment PS and P'S' do not lie on the same segment

Hence, the true statement is (c)

Read more about dilation at:

brainly.com/question/13176891

#SPJ1

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saul85 [17]

Answer:

b

Step-by-step explanation:

4 0
2 years ago
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Help me answer these questions please 15, 19 and 20 please​
SpyIntel [72]

Answer:

15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

Step-by-step explanation:

We are to find the derivative of the questions pointed out.

15) K(t) = 5(5^(t)) - 2(3^(t))

Using implicit differentiation, we have;

K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P(w) = 2e^(w) - (2^(w))/5

P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)

Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)

Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

7 0
3 years ago
Maria and jane bought a whole pizza pie. marie ate 1/5 of the pie and jane ate 1/4 of the pie. write a number sentence to find o
Papessa [141]
Eleven Twentieths of the pie are left, so that's 11/20

Method to solve; 
Since its given a 1/4 and a 1/5 it's easiest to convert these to twentieths (the lowest common multiple of 4 and 5)
So 1/4= 5/20
      1/5 = 4/20
How much is eaten = 5/20 + 4/20 = 9/20
How much remains = Total (20/20) - How much eaten (9/20) = 11/20
8 0
3 years ago
Unit 5
AlladinOne [14]

his average test score would be 82

you add together all the test scores

90 + 76 + 84 + 66 + 96 + 89 + 73 =574

and then you divide that number by how many scores there were

574 ÷ 7 = 82

8 0
2 years ago
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A computer performs a calculation in 2.5*10-5 seconds to solve a math problem. How long does the computer need to calculate the
Nitella [24]

Given :

A computer performs a calculation in 2.5\times 10^{-5} seconds to solve a maths problem.

To Find :

How long does the computer need to calculate the solutions to 3\times 10^6 maths problems.

Solution :

Time taken to perform 1 calculation is 2.5\times 10^{-5}.

t=2.5\times 10^{-5}\ s

So, time taken to perform 3\times 10^6 calculations.

T = t\times( 3\times 10^6)\\\\T = 2.5\times 10^{-5}\times 3\times 10^6\\\\T = 75\ seconds

Hence, this is the required solution.

5 0
2 years ago
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