1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Olenka [21]
3 years ago
10

ANSWER PLZ QUICK AND FAST

Mathematics
1 answer:
Vsevolod [243]3 years ago
7 0

a/3 = -18

a = -18 x 3

a = -54 (D)

You might be interested in
Solve the formula ax+by=c for x​
lozanna [386]

Answer:

c/(a+b)

Step-by-step explanation:

ax + bx = c ➡ x (a+ b) = c ➡ x = c/(a+b)

5 0
3 years ago
Read 2 more answers
Sarah's rectangular garden has a perimeter of 327 +327 +218 +28 cm.
hodyreva [135]

Answer:

Sarah's rectangular garden has a perimeter of 900cm

5 0
3 years ago
Read 2 more answers
Help me please!!! you don’t have to explain
hjlf

Answer:

c  IS THE ANSWER

8 0
3 years ago
Read 2 more answers
Please explain how and give the answer!
nadezda [96]
The mass of b equals the mass of d so
24(10-x)=6(x+15)
240-24x=6x+90
30x=150
x=5
mass of d is 6(5+15)=6*20=120
mass of c=180-mas of d=180-120=60°
7 0
3 years ago
Read 2 more answers
Help me with trigonometry
poizon [28]

Answer:

See below

Step-by-step explanation:

It has something to do with the<em> </em><u><em>Weierstrass substitution</em></u>, where we have

$\int\, f(\sin(x), \cos(x))dx = \int\, \dfrac{2}{1+t^2}f\left(\dfrac{2t}{1+t^2}, \dfrac{1-t^2}{1+t^2} \right)dt$

First, consider the double angle formula for tangent:

\tan(2x)= \dfrac{2\tan(x)}{1-\tan^2(x)}

Therefore,

\tan\left(2 \cdot\dfrac{x}{2}\right)= \dfrac{2\tan(x/2)}{1-\tan^2(x/2)} = \tan(x)=\dfrac{2t}{1-t^2}

Once the double angle identity for sine is

\sin(2x)= \dfrac{2\tan(x)}{1+\tan^2(x)}

we know \sin(x)=\dfrac{2t}{1+t^2}, but sure,  we can derive this formula considering the double angle identity

\sin(x)= 2\sin\left(\dfrac{x}{2}\right)\cos\left(\dfrac{x}{2}\right)

Recall

\sin \arctan t = \dfrac{t}{\sqrt{1 + t^2}} \text{ and } \cos \arctan t = \dfrac{1}{\sqrt{1 + t^2}}

Thus,

\sin(x)= 2 \left(\dfrac{t}{\sqrt{1 + t^2}}\right) \left(\dfrac{1}{\sqrt{1 + t^2}}\right) = \dfrac{2t}{1 + t^2}

Similarly for cosine, consider the double angle identity

Thus,

\cos(x)=  \left(\dfrac{1}{\sqrt{1 + t^2}}\right)^2- \left(\dfrac{t}{\sqrt{1 + t^2}}\right)^2 = \dfrac{1}{t^2+1}-\dfrac{t^2}{t^2+1} =\dfrac{1-t^2}{1+t^2}

Hence, we showed \sin(x) \text { and } \cos(x)

======================================================

5\cos(x) =12\sin(x) +3, x \in [0, 2\pi ]

Solving

5\,\overbrace{\frac{1-t^2}{1+t^2}}^{\cos(x)} = 12\,\overbrace{\frac{2t}{1+t^2}}^{\sin(x)}+3

\implies \dfrac{5-5t^2}{1+t^2}= \dfrac{24t}{1+t^2}+3 \implies  \dfrac{5-5t^2 -24t}{1+t^2}= 3

\implies 5-5t^2-24t=3\left(1+t^2\right) \implies -8t^2-24t+2=0

t = \dfrac{-(-24)\pm \sqrt{(-24)^2-4(-8)\cdot 2}}{2(-8)} = \dfrac{24\pm 8\sqrt{10}}{-16} =  \dfrac{3\pm \sqrt{10}}{-2}

t=-\dfrac{3+\sqrt{10}}{2}\\t=\dfrac{\sqrt{10}-3}{2}

Just note that

\tan\left(\dfrac{x}{2}\right) =  \dfrac{3\pm 8\sqrt{10}}{-2}

and  \tan\left(\dfrac{x}{2}\right) is not defined for x=k\pi , k\in\mathbb{Z}

6 0
2 years ago
Other questions:
  • What is the measure of /_ C?
    8·1 answer
  • PLEASE HELP ME!!!!! INEED HELP ON THIS!!!
    7·1 answer
  • A rectangular box has a height of 10 cm. If the width is 1.5 times the height and the depth is the length of the width, what is
    14·2 answers
  • Abby created a new energy drink by mixing 3 parts guava juice with 5 parts peach
    6·1 answer
  • Brainly isn't working ​
    10·2 answers
  • Which of the following situations could be represented by the expression, 25x+100?
    10·1 answer
  • A company that recently changed it slogan is hosting an optional big company picnic.Some members of the marketing team are eatin
    14·1 answer
  • Lin and her friends went out for ice cream after school. The following questions came up during their trip. Select all the quest
    10·2 answers
  • Find the distance between each pair of points
    5·1 answer
  • Tamika's Terrific Tacos sells a beef or chicken taco for $2.50. The ingredients for each taco cost 50¢. Tamika's taco makers Tom
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!