I'm not sure if this is the easiest way of doing this, but it surely work.
Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

Moreover, let CH=y and BC=z
Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

If we solve the first two equations for y squared, we have

And we can deduce

So that the third equation becomes

(we can't accept the negative root because negative lengths make no sense)

Why?
The first thing we need to do is find the area of the triangle, we can to that by subtracting the area of ABCD from ACBE, then, we can use the formulas to calculate the area for both triangle and rectangle to find "f" and "g".
Calculating we have:

Now, we can calculate "f" by using the formula to calculate the area of the triangle:

Now, finding "g" by using the formula to calculate the area of the rectangle, we have:

Hence, we have that:

Have a nice day!
Answer:
16
Step-by-step explanation:
here is a link that will hopefully help.
https://divisible.info/LongDivision/How-to-calculate-33/divided-by-2-using-long-division.html
Answer:
w = 
(Anyone can correct me if I'm wrong)
Step-by-step explanation:
Before we start the solving, we can make the following statements:
Area = l x w
Area = 5x + 25
therefore,
l x w = 5x + 25
Since the question states that the length is x more than the width, so we can make the following statement:
w = l + x
With this, we can substitute it to the first statement we made, l x w = 5x + 25,
l x (l + x) = 5x + 25
+ lx = 5x + 25
lx - 5x = 25 - 
x(l - 5) = 25 - 
x = 
From this, we can find w by substituting it in the statement we made earlier, w = l + x,
w = 