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Vadim26 [7]
2 years ago
11

Find the perimeter of the triangle whose vertices are (−7,−1), (5,−1), and (5,4). Write the exact answer. Do not round.

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
7 0

The perimeter of the triangle is 30 units

<h3>How to determine the perimeter?</h3>

The vertices are (−7,−1), (5,−1), and (5,4).

Start by calculating the distance between the vertices using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2

So, we have:

d1 = \sqrt{(-1 + 1)^2 + (5 + 7)^2

d1 = 12

d2 = \sqrt{(-1 - 4)^2 + (5 - 5)^2

d2 =5

d3 = \sqrt{(-1 - 4)^2 + (-7 - 5)^2

d3 = 13

The perimeter is then calculated as:

P = d1 + d2 + d3

This gives

P = 12 + 5 + 13

Evaluate

P = 30

Hence, the perimeter of the triangle is 30 units

Read more about perimeter at:

brainly.com/question/6465134

#SPJ1

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Answer:

The error interval for x is:

                 [3.65,3.74]

Step-by-step explanation:

The number after rounding off is obtained as:

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We know that any of the number below on rounding off the number to the first decimal place will result in 3.7:

  3.65     3.66    3.67    3.68    3.69    3.70    3.71   3.72    3.73    3.74

( Because if we have to round off a number present in decimals to n place then if  there is a  number greater than or equal to 5 at n+1 place then it will result to the one higher digit  at nth place on rounding off and won't change the digit if it less than 5 )

        Hence, the error interval is:

            [3.65,3.74]

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