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vivado [14]
4 years ago
12

Please help. I’m confused

Mathematics
1 answer:
Simora [160]4 years ago
6 0

Answer:

when x=6, y=30

when x=7.5, y=37.5

Step-by-step explanation:

Just plug in the value of x into the equation y=5x

so when x=6, the equation will be y=5(6).  In this case y=30

when x =7.5, the equation will be y=5(7.5). So y=37.5

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6 0
3 years ago
in an examination, Adenike obtained 19marks more than musa.if adenike had obtained one and half times her own mark,she would hav
fomenos

Answer: Adenike scored 64 marks, while Musa scored 45 marks

Step-by-step explanation: We shall start by assigning letters to each unknown variable. Let Adenike’s mark be d while Musa’s mark shall be m.

First of all, if Adenike obtained 19 marks more than Musa, then if Musa scored m, Adenike would score 19 + m (or d = 19 + m). Also if Adenike has obtained one and half her own mark (which would be 1 1/2d or 3d/2), it would have been equal to 6 times more than twice Musa’s mark (or 6 + 2m). This can be expressed as

3d/2 = 6 + 2m. So we now have a pair of simultaneous equations;

d = 19 + m ———(1)

3d/2 = 6 + 2m ———(2)

Substitute for the value of d into equation (2), if d = 19 + m

(3{19 + m})/2 = 6 + 2m

By cross multiplication we now have

3(19 + m) = 2(6 + 2m)

57 + 3m = 12 + 4m

We collect like terms and we have

57 - 12 = 4m - 3m

45 = m

We now substitute for the value of m into equation (1)

d = 19 + m

d = 19 + 45

d = 64

So Adenike scored 64 marks while Musa scored 45 marks

6 0
4 years ago
Parallelogram RECT is a rectangle. If EC = x + y , RT = 2x - y, RE = 2x + y, and TC = 3x - 3 , what are the values of the variab
Lady_Fox [76]
<h2>The values of the variable are 3 and 6.</h2>

Step-by-step explanation:

In parallelogram RECT is a rectangle,

EC = x + y , RT = 2x - y, RE = 2x + y and TC = 3x - 3

To find, the values of the variable = ?

∵ The opposite sides are equal.

∴ RE = TC and RT = EC

2x + y = 3x - 3

⇒ x - y = 3                   .......... (1)

Also,

2x - y = x + y

⇒ x - 2y = 0               .......... (2)      

Subtracting (1) from (2), we get

∴ x - y - (x - 2y ) = 3 - 0

⇒ x - y - x + 2y = 3

⇒ y = 3

Put y = 3 in equation (1), we get

x - 3 = 3  

⇒ x = 3 + 3 = 6

∴ x = 6 and y = 3

Thus, the values of the variable are 3 and 6.

8 0
4 years ago
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