Answer
given,
mass of the stick = 290 grams = 0.29 Kg
Force on the stick on one side = F = 9 N
force acting perpendicular to stick.
magnitude of acceleration
rate of change of angular momentum is equal to Force
rate of change of angular momentum = 9 N
F = m a
a = 31.034 m/s²
Direction of motion will in the direction of force application or in the direction of change of velocity
Answer:
34.3 m/s
Explanation:
Newton's Second Law states that the resultant of the forces acting on the car is equal to the product between the mass of the car, m, and the centripetal acceleration (because the car is moving of circular motion). So at the top of the hill the equation of the forces is:
where
(mg) is the weight of the car (downward), with m being the car's mass and g=9.8 m/s^2 is the acceleration due to gravity
R is the normal reaction exerted by the road on the car (upward, so with negative sign)
v is the speed of the car
r = 0.120 km = 120 m is the radius of the curve
The problem is asking for the speed that the car would have when it tires just barely lose contact with the road: this means requiring that the normal reaction is zero, R=0. Substituting into the equation and solving for v, we find: