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4 years ago

How many elections do atoms typically “want” in their valence shell? This is timed, please help!

Physics

1 answer:

9966 [12]4 years ago

4 0

Answer:

They typically "want" 2, so the answer is C.

Explanation:

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Please Help No Links

ale4655 [162]

Answer:

the moment of inertia

Explanation:

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3 years ago

Standing at the same location, which organism would have the GREATEST gravitational attraction to the earth?

Nastasia [14]

To claculate the gravitational attraction between two bodies with mass 1(m1) and mass 2 (m2) you need to use the equation:

F= G ((m1*m2)/r^2)

Where;
G is the gravitational constant (6.67E-11 m^3 s-2 Kg-1) and
r is the distance between the two objects.

7 0

3 years ago

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A cell phone sending a text message what kinda energy is to the scenario?

creativ13 [48]

Answer:

low powered radio frequency (RF) energy

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3 years ago

A spring has a natural length of 0.5 m and was stretched by 0.02 m. if the spring had a resultant energy of 0.5 j what is the sp

Anna71 [15]

$\textbf{2500 }\dfrac{\textbf{kg}}{\textbf{s}^{\textbf{2}}}$

Explanation:

Natural length of a spring is $0.5\text{ }m$ . The spring is streched by $0.02\text{ }m$ . The resultant energy of the spring is $0.5\text{ }J$ .

The potential energy of an ideal spring with spring constant $k$ and elongation $x$ is given by $\dfrac{1}{2}kx^{2}$ .

So, in the current problem, the natural length of the spring is not required to find the spring constant $k$ .

$\text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}$

∴ The spring constant of the spring = $2500\text{ }\frac{kg}{s^{2}}$

4 0

4 years ago

ANSWER QUICK PLS

vichka [17]

Answer:

what was the answer? Was it 0.98?

7 0

3 years ago

Read 2 more answers