A soccer ball is kicked 8 m north. Then a teammate kicks it 6 m east into the goal. What is the soccer ball’s displacement from
2 answers:
Answer:
Displacement=10 meters
Explanation:
The displacement is the direct path from the first contact with the ball and the last spot it was seen in. The ball was kicked north 8 meters, meaning it was kicked vertically upward, and then it was kicked east 6 meters, or to the right. If we were to draw the displacement we would see that this is a right triangle. That means we can use the Pythagorean Theorem:
Boom.
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Answer:The mass of ball B is 10 kg.
Explanation;
Mass of ball A =
Velocity of the ball A before collision:
Velocity of ball A after collision=
Mass of ball B=
Velocity of the ball B before collision:
Velocity of ball B after collision=
The mass of ball B is 10 kg.
Answer:
(a) 1500 m
(b) 2827.43m
Explanation:
Given that the time for one cycle of the swing is 1 s
The radius of the swing, R= 3.0m
The angle covered, \theta, by each swing is a quarter of the circle. i.e.
Speed of running of women =5 m/s.
Time of running = 5 minutes= 5 x 60 secondes= 300 s.
(a) As distance= (speed) x (time)
So, the required distance= 5 x 300 m= 1500 m.
(b) As there are two swings in one cycle, so, the distance covered in one swing is the length of the circular shown in the figure.
As arc length, , where \theta is the angle, in radian, subtended by the arc at the center, and R is the radius of curvature of the arc.
So, the distance covered by the child in 1 swing .
In 1 cycle, there are 2 swings, so distance covered in 1 cycle .
Now, in 1 second there is 1 cycle, so in 5 minutes there will be 300 cycles.
So, the total distance covered by the child
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