There are (35)2 ⋅ 30 leaves on a tree. What is the total number of leaves on the tree? 3^3 , 3^7, 3^10 3^25

Doss [256]

Cos (x+y)/cos x sin y

= cos x cos y - sin x sin y / cos x sin y

= cos x cos y/cos x sin y - sin x sin y / cos x sin y

hope this helps

8 0

4 years ago

Read 2 more answers

Let f be the function defined by f(x) = 3x^5-5x^3+2

sveticcg [70]

(a) When f is increasing the derivative of f is positive.

f'(x) = 15x^4 - 15x^2 > 0
15x^2(x^2 - 1)> 0
x^2 - 1 > 0 (The inequality doesn't flip sign since x^2 is positive)
x^2 > 1
Then f is increasing when x < -1 and x > 1.

(b) The f is concave upward when f''(x) > 0.
f''(x) = 60x^3 - 30x > 0
30x(2x^2 - 1) > 0
x(2x^2 - 1) > 0
x(x^2 - 1/2) > 0
x(x - 1/sqrt(2))(x + 1/sqrt(2)) > 0

There are four regions here. We will check if f''(x) > 0.
x < -1/sqrt(2): f''(-1) = -30 < 0
-1/sqrt(2) < x < 0: f''(-0.5) = 7.5 > 0
0 < x < 1/sqrt(2): f''(0.5) = -7.5 < 0
x > 1/sqrt(2): f''(1) = 30 > 0

Thus, f''(x) > 0 at -1/sqrt(2) < x < 0 and x > 1/sqrt(2).
Therefore, f is concave upward at -1/sqrt(2) < x < 0 and x > 1/sqrt(2).

(c) The horizontal tangents of f are at the points where f'(x) = 0
15x^2(x^2 - 1) = 0
x^2 = 1
x = -1 or x = 1
f(-1) = 3(-1)^5 - 5(-1)^3 + 2 = 4
f(1) = 3(1)^5 - 5(1)^3 + 2 = 0

Therefore, the tangent lines are y = 4 and y = 0.

8 0

4 years ago

Read 2 more answers

Towers A and B are located 5 miles apart. A ranger spots a fire at a 42-degree angle from tower A. Another fire ranger spots the

lord [1]

Answer: The fire is 3.5 miles from tower B

Step-by-step explanation: Please refer to the attached diagram. The triangle in the attached diagram illustrates the clues given in the question. Both rangers are standing at points A and B respectively with a distance of 5 miles between them, which is line AB. Also, one ranger spots a fire from a tower at an angle of 42 degrees, which is point A. Another ranger spots the same fire from another tower, but from an angle of 64 degrees, which is point B. The fire is at point C on the triangle. Now we have a triangle with only one side known (5 miles) and three angles known (the third angle is computed as 180 - {64+42} which equals 74) which are 64 degrees, 42 degrees and 74 degrees.

The distance from the fire to tower B is calculated using the law of sines. (Note that this is not a right angled triangle, hence we cannot use trigonometric ratios). The law of sines is expressed as follows;

a/SinA = b/SinB or

a/SinA = c/SinC

Depending on the sides and angles we are given and the ones we are to calculate.

The distance from the fire to tower B is line BC, labeled as a in our diagram. Using the law of sines

a/SinA = c/SinC

(Note also that a is directly facing angle A, c is directly facing angle C, and so on)

a/SinA = c/SinC

a/Sin 42 = 5/Sin 74

By cross multiplication we now have

a (Sin 74) = 5 (Sin 42)

Divide both sides of the equation by Sin 74 and we now arrive at

a = 5 (Sin 42)/Sin 74

a = 5 (0.6691)/0.9613

a = 3.3455/0.9613

a = 3.4802

{rounded to the nearest tenth of a mile, a equals 3.5}

Therefore the distance from tower B to the fire is approximately 3.5 miles

3 0

3 years ago

When x=2 and y=4, what is the value of 7x-y?

kicyunya [14]

Answer:

the value of 7x-y is -14.

Step-by-step explanation:

When x=2 and y=4,

To find the value of 7x - y when x =2, y = 4, this means when ever you see x, put 2 in replacement, y, put 4 respectively.

7x - y = 7(2 - 4)

14 - 28

= -14.

6 0

3 years ago

At Heard High School, the probability that a student takes Advanced Weight Training and Advanced Spanish is 0.099. The probabili

suter [353]

The probability that the students take both Advanced Weight Training and Advanced Spanish is the product of their individual probabilities.
P(A and B) = 0.099 = P(A) x P(B)
where A and B are the events in which a student takes Advance Weight Training and Advanced Spanish.
P(B) = P(A and B) / P(A)
Substituting the known values,
P(B) = 0.099 / 0.71 = 0.14
Thus, the answer is 0.14.

0 0

4 years ago