Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
Answer:
97/40
Step-by-step explanation:
so 2.125= 17/8
3/10+17/8 need to find common denominator so
times 8/8 to 3/10
times 10/10 to 17/8
24/80+170/80= 194/80 (common denominator so can add)
divide 194/80 because want reduce form
97/40 is the answer
(When i look at it now i can just time 4/4 and 5/5 but its ok this still gets the answer)
Answer:
y = - 9.1768x2 + 122.2567x + 14.9091
Step-by-step explanation:
Given the following :
Month (x) Daily Rental Price (y) 1 $154 2 $205 3 $266 4 $358 5 $403 6 $425 7 $437 8 $430 9 $381 10 $285 11 $211 12 $195
Using the online regression equation graphing tool ; The quadratic model obtained in the form,
y = Ax^2 + Bx + C is :
y = - 9.1768x2 + 122.2567x + 14.9091
Attached below is a picture of the quadratic regression curve.
You need to subtract the bonus points form the final score: 91-4=87
The true statement about her method would be to start at the origin. But you would go up 4 spaces you would go to the right 4 spaces.