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3 years ago

6

Suppose you roll a die. Find the probability of the given event. Simplify your answer.

1 answer:

Elodia [21]3 years ago

7 0

Answer:

Step-by-step explanation:

Events: 1,2,3,4,5,6

Odd number are numbers not divisible by 2

Odd number < 5 are 1 & 3

P(odd numbers <5)= 2/6

= 1/3

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Solve the triangle. Round your answers to the nearest tenth. Law of sines 6 A. M∠C=34 m ∠ C = 34 , b=25 b = 25 , c=16 c = 16 B.

PolarNik [594]

Answer:

$A = 43.0^o$

$B = 55.0^o$

$BC = 20.0$

Step-by-step explanation:

I will solve this question with the attached triangle

From the attachment, we have:

$\angle C =82^o$

$AB = 29$

$AC = 24$

Required

Solve the triangle

First, we calculate $\angle B$ using sine law:

$\frac{AC}{\sin(B)} = \frac{AB}{\sin(C)}$

This gives:

$\frac{24}{\sin(B)} = \frac{29}{\sin(82^o)}$

$\frac{24}{\sin(B)} = \frac{29}{0.9903}$

Cross multiply

$\sin(B) * 29 = 24 * 0.9903$

$\sin(B) * 29 = 23.7672$

Divide both sides by 29

$\sin(B) = 0.8196$

Take arcsin of both sides

$B = \sin^{-1}(0.8196)$

$B = 55.0^o$

Next, calculate $\angle A$ using:

$A + B + C = 180^o$ --- angles in a triangle

$A + 55^o + 82^o = 180^o$

Collect like terms

$A = 180^o-55.0^o - 82^o$

$A = 43.0^o$

Next, calculate BC using sine laws

$\frac{BC}{\sin(A)} = \frac{AB}{\sin(C)}$

This gives:

$\frac{BC}{\sin(43.0)} = \frac{29}{\sin(82)}$

$\frac{BC}{0.6820} = \frac{29}{0.9903}$

Make BC the subject

$BC = \frac{29*0.6820}{0.9903}$

$BC = 20.0$

6 0

3 years ago

A submarine lies 3 kilometers from the path of a target ship. The sub’s torpedoes have a range of 5 kilometers. For what distanc

aev [14]

The distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

Explanation:

The submarine lies 3 km from the target ship.

Let B denotes the target ship and C denotes the submarine.

Let AC denotes the the target ship would be within the range of the torpedoes.

The image attached below illustrates that the distance between submarine and the target ship and the range of the torpedoes.

Let BC denotes the distance between the target ship and the submarine. Let AC denotes the range of the torpedoes.

To determine the length of AB, let us use Pythagorean theorem,

$AC^{2} =AB^{2} +BC^{2}$

Substituting the values of BC = 3 and AC = 5, we have,

$5^{2} =AB^{2} +3^{2}$

Squaring the terms, we get,

$25 =AB^{2} +9$

Subtracting both sides by 9, we have,

$16 =AB^{2}$

Taking square root on both sides,

$AB = 4$

Thus, the distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

5 0

3 years ago

Help me solve this pls

kirill [66]

I think the answer is b

8 0

2 years ago

Mikey bought 4 of the 500 raffle tickets sold to

Zina [86]

Answer:

4/500

Step-by-step explanation:

6 0

3 years ago

A snack bar offers chili and/or cheese on ithot dogs for an additional fee.

Sloan [31]

Answer:

Hi Im Pride and i would like to take you to your answer your answer to this question is

20% of his customer ordered cheese but no chilli on their hot dogs

Step-by-step explanation:

please mark brainly

5 0

2 years ago