-3x+5y=-4
5y=3x-4
Y=3/5x-4/5

When it parallel to the line y=3/5x-4/5

It can be y=-3/5x+b

-5=6/5+b

B=-5-6/5=-25/5-6/5=-31/5

Y=-3/5x-31/5

3/5x+y=-31/5

Multiply 5

3x+5y=-31

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3 years ago

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Ostrovityanka [42]

The vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.

Given an equation showing profits of A Christmas vendor as

P=-0.1 $g^{2}$ +30g-1200.

We have to find the number of gingerbread houses that the vendor needs to sell in order to earn profit of $665.60 and $1500.

To find the number of gingerbread houses we have to put P=665.60 in the equation given which shows the profit earned by vendor.

665.60=-0.1 $g^{2}$ +30g-1200

0.1 $g^{2}$ -30g+1200+665.60=0

0.1 $g^{2}$ -30g+1865.60=0

Divide the above equation by 0.1.

$g^{2}$ -300g+18656=0

Solving for g we get,

g=[300± $\sqrt{(300)^{2}-4*1*18656 }$ ]/2*1

g=[300± $\sqrt{90000-74624}]/2$

g=[300± $\sqrt{15376}$ ]/2

g=(300±124)/2

g=(300+124)/2 , g=(300-124)/2

g=424/2, g=176/2

g=212,88

Because 212 is much greater than 88 so vendor prefers to choose selling of 88 gingerbread houses.

Put the value of P=1500 in equation P=-0.1 $g^{2}$ +30g-1200.

-0.1 $g^{2}$ +30g-1200=1500

0.1 $g^{2}$ -30g+1500+1200=0

0.1 $g^{2}$ -30g+2700=0

Dividing equation by 0.1.

$g^{2}$ -300g+27000=0

Solving the equation for finding value of g.

g=[300± $\sqrt{300^{2} -4*1*27000}$ ]/2*1

=[300± $\sqrt{90000-108000}] /2$

=[300± $\sqrt{-18000}$ ]/2

Because $\sqrt{-18000}$ comes out with an imaginary number so it cannot be solved for the number of gingerbread houses.

Hence the vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.

Learn more about equation at brainly.com/question/2972832

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1 year ago