Answer:
i think it would be 11 cups
So there are 12 spaces right. In first blank u have a choice to fill any of the alphabet .(first twelve alphabets) <span>and it goes down to just 1 letter in the last space. but do i just multiply them.
hope dis helps</span>
My guess is that there is 5 angles and 5 sides... because i divided 10 in half
likeee this
10 ÷ 2 = 5
and bam we have our answer
Given:
The function is:

To find:
The value of
.
Solution:
We have,

Putting
, we get



On combining like terms, we get


Therefore, the required function is
.
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:

Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:


Now we can apply the quadratic formula

where a=-16, b=122, and c=198


or


or


or

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.