A firecracker shoots up from a hill 160 feet high, with an initial speed of 90 feet per second. Using the formula H(t) = −16t2 +
vt + s, approximately how long will it take the firecracker to hit the ground?
A Five seconds
B Six seconds
C Seven seconds
D Eight seconds
2 answers:
When the firecracker hits the ground, H(t) = 0.0 = -16t^2 + 90t + 160 Using the quadratic formula,t = (-90 +- sqrt(90^2 - 4(-16)(160))) / 2(-16)t = -1.42 ort = 7.04
The negative time is extraneous. Therefore,t = 7.04 s.
Seven Seconds is your answer!
I did the test and 7 seconds was the right answer hope this helps
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