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Oduvanchick [21]
3 years ago
13

If a truck gets 14 mile to the gallon on average, how much does carbon dioxide is emitted into the atmosphere when the truck tra

vels at 200 miles?
Mathematics
2 answers:
Masja [62]3 years ago
8 0
Converting 200 miles to the amount of carbon dioxide emission that would be 1.884 tons annually. This will be the amount of carbon dioxide given that 200 miles is monthly covered.
IgorLugansk [536]3 years ago
5 0

Answer:

Carbon dioxide emitted in the atmosphere is 129.6 kg.

Step-by-step explanation:

As we know when we burn 1 gallon of gasoline produces 20 pounds of carbon dioxide.

Since in i gallon a truck covers 14 miles which means in 14 miles a truck produces 20 pounds of carbon dioxide gas.

Now we can calculate the amount of CO2 emitted by a truck in 200 miles.

∵ During 14 miles CO2 emitted = 20 pounds

∴ during 1 mile CO2 emitted will be = 20/14 pounds

∴ While covering 200 miles CO2 emitted = (200×20)/14 = 285.71 pounds of CO2.

Or by converting 281.71 pounds to kg amount of CO2 will be = 129.6 kg

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Denise received 300 votes in election for student council president she was 60% of the students who voted in the election how ma
nata0808 [166]

Answer: 500 votes

Step-by-step explanation:

This can be shown by this formula.

300 is 60% of x. So if u can find the 100% by taking 300 and multiplying it by 100 which would be the 100% and dividing it by 60 which would be the 60%. The number that you get is how many didn't vote for Denise. Now just add these which would be 300+200 which would give you the answer above.

5 0
3 years ago
Complete the statements to find the measurements of Za and Zb.
Sunny_sXe [5.5K]
What do you want me to find
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A small business just celebrated its 1-year anniversary they calculate that in one year they serve over 5110 customers on averag
Juli2301 [7.4K]
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8 0
3 years ago
Which statement best explains the relationship between lines FG and HJ?
murzikaleks [220]

Answer:

(D)

Step-by-step explanation:

From the figure, we have

The coordinates of the point F are: (-4,1).

The coordinates of the point G are: (0,-2)

The coordinates of the point J are: (0,4) and

The coordinates of the point H are: (-4,-2).

Now, the slope of the line FG is :

S=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

S=\frac{-2-1}{0+4}

S=\frac{-3}{4}

And, the slope of the line HJ is:

S=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

S=\frac{-2-4}{-4-0}

S=\frac{3}{2}

Now, the slope of FG=\frac{1}{slope of HJ}

\frac{-3}{4}=\frac{2}{3}

which is not possible, thus They are not perpendicular because their slopes are not negative reciprocals.

6 0
3 years ago
Read 2 more answers
Can you explain it for me?
nikdorinn [45]
B is the right answer
5 0
3 years ago
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