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Leokris [45]
2 years ago
11

Add 7 2/3+4/7 reduce to the lowest terms

Mathematics
2 answers:
viva [34]2 years ago
8 0

\huge\text{Hey there!}

\huge\textbf{Equation:}

\mathbf{7 \dfrac{2}{3} + \dfrac{4}{7}}

\huge\textbf{Solving:}

\mathbf{7 \dfrac{2}{3} + \dfrac{4}{7}}

\mathbf{= \dfrac{7\times3+2}{3} + \dfrac{4}{7}}

\mathbf{= \dfrac{21 + 2}{3} + \dfrac{4}{7}}

\mathbf{= \dfrac{23}{3} + \dfrac{4}{7}}

\mathbf{= \dfrac{173}{21}}

\mathbf{\approx 8 \dfrac{5}{21}}

\huge\textbf{Answer:}

\huge\boxed{\mathsf{8 \dfrac{5}{21}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

KonstantinChe [14]2 years ago
6 0

Answer:

8\frac{5}{21}

Step-by-step explanation:

7\frac{2}{3} +\frac{4}{7} = 7\frac{14}{21} +\frac{12}{21} = 8\frac{5}{21}

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Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

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the second is when n = 20 and x = 5, this is all possible scenarios.

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15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

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