I hate math so I really need help

somebody read 50 pages of a book in 50 minutes she reads at a constant rate how many pages did she read per minute

miv72 [106K]

If she reads 50 pages of a book in 50 minutes, just divide 50 by 50.

50 / 50 = 1 She reads one page of a book a minute.

4 0

4 years ago

Find the acute angle between the two given lines<br><br> y=-2x and y=x

Marina CMI [18]

Answer:

θ ≈ 71.6°

Step-by-step explanation:

The angle between two lines with slopes m₁ and m₂ is:

tan θ = | (m₂ − m₁) / (1 + m₁m₂) |

Here, m₁ = -2 and m₂ = 1.

tan θ = | (1 − (-2)) / (1 + (-2)(1)) |

tan θ = | 3 / -1 |

tan θ = 3

θ ≈ 71.6°

3 0

4 years ago

Jerry has a miniature model of a boat. He knows that the boat is 3 3/4 inches wide and 5 1/2 inches long. What is the actual len

FromTheMoon [43]

Width of the miniature model = $3\frac{3}{4}$ inches

Length of the miniature model = $5\frac{1}{2}$ inches

The actual width of the boat = 15 feet

Let us find the actual length of the boat.

Write it in a proportion form.

width of model : length of model : : width of actual : length of actual

$$\Rightarrow 3\frac{3}{4}:5\frac{1}{2}::15:x$

$$\Rightarrow\frac{15}{4}:\frac{11}{2}::15:x$

$$\Rightarrow\frac{\frac{15}{4}}{\frac{11}{2}} =\frac{15}{x}$

Do cross multiplication.

$$\Rightarrow{\frac{15}{4}x =15\times\frac{11}{2}$

$$\Rightarrow{\frac{15}{4}x =\frac{165}{2}$

$$\Rightarrow x =\frac{165}{2}\times{\frac{4}{15}$

⇒ x = 22

Hence the actual length of the boat is 22 feet.

6 0

3 years ago

In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until

Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this problem:

There are 12 bulbs, hence N = 12.

3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.

The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182$

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0

2 years ago

Find the slope of the line that goes through the given points. (-10, -3) and (-7, -9)

Hatshy [7]

Answer:

-2

Step-by-step explanation:

rise over run or, y2-y1/x2-x1

7 0

3 years ago