Answer:
You will need to sample at least 3108 students.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
In this problem, we have that:
99% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The margin of error is:
How many students will I need to survey if I want to estimate, with 99% confidence, the true proportion to within 2%?
You need a sample size of at least n.
n is found when M = 0.02. So
You will need to sample at least 3108 students.
