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Tatiana [17]
3 years ago
7

Frankie is practicing for a 5-kilometer race. His normal time is 31 minutes 21 seconds. Yesterday it took him only 29 minutes 38

seconds.How much faster was Frankie yesterday than his normal time?
Mathematics
2 answers:
klasskru [66]3 years ago
6 0
Frankie is 2 minute and 23 seconds faster.
vivado [14]3 years ago
3 0

Answer:

Frankie is 1 minute and 43 seconds faster.

Step-by-step explanation:

Normal Time taken by frankie to complete 5km=31 minutes 21 seconds

yesterday,  Time taken by frankie to complete 5km=29min 38seconds

therefore time difference=31 minutes 21 seconds-29min 38seconds

=1minute 43seconds

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Answer:

The answer is "0.3206".

Step-by-step explanation:

H_0: p_1 = p_2\\\\H_a: p_1 \neq  p_2\\\\\hat{p_1} = \frac{X_1}{N_1} = \frac{53}{400} = 0.1325\\\\\hat{p_1}= \frac{X_2}{N_2} = \frac{78}{500}= 0.156\\\\\hat{p} = \frac{(X_1 + X_2)}{(N_1 + N_2)} = \frac{(53+78)}{(400+500)} = 0.1456

Testing statistic:

z = \frac{(\hat{p_1}- \hat{p_2})}{\sqrt{(\hat{p} \times (1-\hat{p}) \times (\frac{1}{N_1} + \frac{1}{N_2}))}}

=\frac{(0.1325-0.156)}{\sqrt{(0.1456\times (1-0.1456)\times (\frac{1}{400} + \frac{1}{500}))}}\\\\ = -0.99

Calculating the P-value Approach

\text{P-value}= 0.3206

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2 years ago
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kaheart [24]

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Step-by-step explanation:

8 0
3 years ago
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Step-by-step explanation:

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