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Sav [38]
2 years ago
10

Richard’s checking account balance was $57.34 at the beginning of the week. During the week, he recorded the transactions below.

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
5 0

Richard’s account balance at the end of the week is $ 132.45

<h3>What is Account Balance ?</h3>

The amount of money in a person's bank account is called the account balance of that person

It is given that

Account balance of Richard’s at the beginning of the week = $57.34

Deposits in the week  : $ 163.75

Expenses in the week : Groceries + Credit card bill + Gas

Total Expenses in the week = 25.37 + 50 + 13.27

                                               = $ 88.64

The Richard’s account balance at the end of the week = Account Balance +Total Deposits - Total Withdrawals

= 57.34 + 163.75 - 88.64

Therefore , Richard’s account balance at the end of the week is $ 132.45.

To know more about Account Balance

brainly.com/question/23271078

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Answer:

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The random variable <em>X</em> is defined as the number among the four homeowners  who have earthquake insurance.

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The random sample of homeowners selected is, <em>n</em> = 4.

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(a)

All the statements above clearly indicate that the random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 4 and <em>p</em> = 0.33.

The probability mass function of <em>X</em> is:

P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...

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The most likely value of a random variable is the expected value.

The expected value of a Binomial random variable is:

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(c)

Compute the probability that at least two of the four selected have earthquake insurance as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{4\choose 0}\ (0.33)^{0}\ (1-0.33)^{4-0}-{4\choose 1}\ (0.33)^{1}\ (1-0.33)^{4-1}\\\\=1-0.20151121-0.39700716\\\\=0.40148163\\\\\approx 0.4015

Thus, the probability that at least two of the four selected have earthquake insurance is 0.4015.

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