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Talja [164]
3 years ago
6

Find the missing length, simplify completely

Mathematics
1 answer:
nataly862011 [7]3 years ago
4 0
The answer is 22 because as u can see they are going up by 1 so 20,21, next 22
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Translate the sentence into an inequality twice the difference of a number and 6 is at least -22 use the variable x for the unkn
almond37 [142]

Answer:

2(n - 6) >= 22

Step-by-step explanation:

2n - 12 >= 22

2n >= 22+12

2n >= 34

n >= 34/2

n >= 17

5 0
3 years ago
1<br>Prove that<br>1: sin/1-cot + cos/1-tan=cos+sin​
Anit [1.1K]

Answer:

have:

\frac{sin}{1-cot}+\frac{cos}{1-tan}\\\\=\frac{sin}{1-\frac{cos}{sin} }+\frac{cos}{1-\frac{sin}{cos} }\\\\=\frac{sin^{2} }{sin-cos}+\frac{cos^{2} }{cos-sin} \\\\=\frac{sin^{2} }{sin-cos}-\frac{cos^{2} }{cos-sin}\\\\=\frac{sin^{2}-cos^{2}  }{sin - cos}\\\\=\frac{(sin-cos)(sin+cos)}{sin-cos}\\\\=sin+cos

Step-by-step explanation:

4 0
3 years ago
Plsss helpppppppppp if you do, you a cool guy or girl
STatiana [176]

9514 1404 393

Answer:

  • Tyler
  • 2 hundredths of a mile

Step-by-step explanation:

The graph is a little difficult to read, but we note that there are 6 grid lines between times that are 2 minutes apart. So, each grid line stands for 2/6 = 1/3 minute.

At the 1-mile mark, the graph crosses 1 grid line above 8 minutes, indicating it takes Tyler 8 1/3 minutes to run 1 mile.

Then in 10 minutes, Tyler will run ...

  distance = speed · time = 1 mile/(8 1/3 min) · 10 min

  = 1/(25/3)·10 = 10·3/25 = 30/25 = 1.2 . . . . miles

__

The equation tells you that Elena runs each mile in 8.5 minutes. To see how far she runs in 10 minutes, we can solve ...

  10 = 8.5x

  x = 10/8.5 ≈ 1.18 . . . . miles

So, Tyler runs farther in 10 minutes by a distance of ...

  1.20 -1.18 = 0.02 . . . . miles

8 0
3 years ago
Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or
soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

\lim_{x \to 3} f(x)

f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L

and the limit does not exist if

\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)

Evaluate the one-sided limits.

The left-hand limit

\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0

The right-hand limit

\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6

Because the limits are not the same the limit does not exist.

8 0
3 years ago
Plz help fast will mark brainliest!!!
ki77a [65]
The answer :9.1×10 ^3

3 0
3 years ago
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