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1 year ago

The black graph is the graph of y= f(x). Choose the equation for the red graph.

Mathematics

2 answers:

Mandarinka [93]1 year ago

6 0

The equation is c y=f(x-1)

Pani-rosa [81]1 year ago

3 0

<h2>answer is option C </h2>

here is your answer

<h3>mark as brilliant </h3><h2>and like pls in my answer</h2>

<h3>if u want complete solution pls message me</h3>

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2 years ago

Erica needs 5 1/2 gallons of paint to paint her house. She has 3 1/2 gallons of paint at school and her friend can give her 1 3/

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Erica needs 1/4 more gallons of paint.

Step-by-step explanation:

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5 1/4 + 1/4 = 5 1/2

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2 years ago

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April lost 5 pounds in her first week of college. Over the next three weeks she lost 3 pounds, gained 2 pounds, and then lost 1

Doss [256]

Change in April's weight is -7

<em><u>Solution:</u></em>

Let the initial weight be "x"

April lost 5 pounds in her first week of college

First week = lost 5 pounds

Therefore, x - 5

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<em><u>Next three week:</u></em>

Lost 3 pound

Gained 2 pound

Lost 1 pound

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x - 5 - 3 + 2 - 1 = x -7

After 4 week, the weight is x - 7

<em><u>The change in April weight is given as:</u></em>

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3 years ago

A sample of 20 account balances of a credit company showed an average balance of $1,170 and a standard deviation of $125. You wa

Lady_Fox [76]

Answer:

The P-value for this test is P=0.2415.

Step-by-step explanation:

We have to perform an hypothesis testing on the mean of alla account balances.

The claim is that the mean of all account balances is significantly greater than $1,150.

Then, the null and alternative hypothesis are:

$H_0: \mu=1150\\\\H_a: \mu>1150$

The sample size is n=20, with a sample mean is 110 and standard deviation is 125.

We can calculate the t-statistic as:

$t=\dfrac{\bar x-\mu}{s/\sqrt{n}}=\dfrac{1170-1150}{125/\sqrt{20}}=\dfrac{20}{27.95}=0.7156$

The degrees of freedom fot this test are:

$df=n-1=20-1=19$

For this one-tailed test and 19 degrees of freedom, the P-value is:

$P-value=P(t>0.7156)=0.2415$

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