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Kryger [21]
1 year ago
13

How many revolutions will a car wheel of diameter 22 in. make as the car travels a distance of one mile

Mathematics
1 answer:
Marianna [84]1 year ago
8 0

It would be take upto 999 revolutions.

<em>Let try to solve it,</em>

Let n represent number of revolutions.

We are asked to find the number of revolutions it will take for a car wheel of diameter 30 in. to travel a distance of one mile.

1 mile = 63360 inches.

We will use circumference of circle formula to solve our given problem.

Circumference = pi*d , where, D represents diameter of circle.

Now, we will set the product of n and circumference of circle equal to 63360 inches as:

pi*22*n= 63360

n= 63360*7/ 22*22

n= 443520/444

n= 998.91

Therefore It would be take upto 999 revolutions.

Learn more about Circumference of circle on:

brainly.com/question/18571680

#SPJ4

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tia_tia [17]

Using proportions, it is found that the two cities are 27.5 miles apart.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

From the given scale, we have that <u>each inch of distance represents 10 miles</u>. Hence the distance in miles for a distance of 2 and 3/4 miles = 2.75 miles is given by:

D = 10 x 2.75 = 27.5 miles.

Hence, the two cities are 27.5 miles apart.

More can be learned about proportions at brainly.com/question/24372153

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Write the equation in standard form. Identity the center and radius.<br> x² + y2 + 8x-4y-7=0
lorasvet [3.4K]

Answer:

equation;

(x + 4) {}^{2}  + (y - 2) {}^{2}  = 27

Center (-4,2)

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3 \sqrt{3}

Step-by-step explanation:

Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

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{x}^{2}  + 8x  +  {y}^{2}  - 4y - 7 = 0

Add 7 to both sides

{x}^{2}  + 8x +  {y}^{2}  - 4y = 7

( {x}^{2}  + 8x) +(  {y}^{2}  - 4y) = 7

Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

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and

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so we have

{x}^{2}  + 8x + 16 +  {y}^{2}  - 4y + 4y = 7 + 16 + 4

{x}^{2}  + 8x + 16  +  {y}^{2}  - 4y + 4y = 27

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so the center is (-4,2)

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\sqrt{27}  = 3 \sqrt{3}

So the radius is 3 times sqr root of 3.

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