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gavmur [86]
4 years ago
5

What is an equation of a parabola with vertex at the origin and focus (0, 7)

Mathematics
1 answer:
MakcuM [25]4 years ago
8 0
<h3>Answer: B)  y = (1/28)x^2</h3>

Explanation:

p = focal distance = 7

the focal distance is from the vertex to the focus

The parabola opens upward (since the vertex is below the focus) so 'a' is positive and a = 1/(4p) = 1/(4*7) = 1/28

The vertex is (h,k) = (0,0)

Put this all together into the formula below and simplify

y = a(x-h)^2 + k

y = (1/28)(x - 0)^2 + 0

y = (1/28)x^2

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Dmitry_Shevchenko [17]

Answer:

Part 1) f(g(x))=3(x^2)+2

Part 2) g(f(5))=289

Step-by-step explanation:

we know that

A composite function is a function that depends on another function. A composite function is created when one function is substituted into another function

we have

f(x)=3x+2

g(x)=x^{2}

Part 1) Determine f(g(x))

To find f(g(x)) substitute the function g(x) as the variable in function f(x)

so

f(g(x))=3(x^2)+2

Part 2) Determine g(f(x))

To find g(f(x)) substitute the function f(x) as the variable in function g(x)

so

g(f(x))=(3x+2)^2

For x=5

g(f(5))=(3(5)+2)^2

g(f(5))=289

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