3 is incorrect, should be 28.9
16^2 + 18^2 = EG^2
256 + 324
580 = EG^2
EG ≈ 24.08
16^2 + 24.08^2 = AG^2
256 + 580 = AG^2
836 = AG^2
AG ≈ 28.9
5 is incorrect:
The base is 8.
Draw an altitude the base.
Since the triangle is isoceles, it divides the base in half.
Half of that base is 4.
Two right triangles have been formed with one leg 4 and hypotenuse 8.
4^2 + b^2 = 8^2
16 + b^2 = 64
b^2 = 48
b ≈ 6.93
The height of the triangle is 6.93, the base is 8.
A = bh/2 = 8*6.93/2 ≈ 27.7 ≈ 28
Answer:
The value of the car is 0.94 times the value of the car the previous year.
Answer:
117.5 or 235/2
Step-by-step explanation:
We can set up an equation for this problem:
Lets Joe's weight be x
then:
2x -5 = 230
therefore:
2x = 235
x = 117.5 or 235/2
It is mentioned in the problem that the shape is a square, hence, we could say that all side's measurement is the same and it is equal. It can be written in a different arrangement of terms, but still, the value to be solved is the same. The sides can be written in the following forms:
S1=6(3X+8)+32+12X
S2=18X+48+32+12X
S3=18X+80+12X
S4=30X+80
The answer is 80 hope this helps :)