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timurjin [86]
3 years ago
14

A hub transmits all incoming messages to all of its ports except the port where the messages came in. A switch usually sends mes

sages only to the destination computer. What information does a switch collect from messages crossing its interfaces so it knows where to send data in future transmissions?
Computers and Technology
2 answers:
andrey2020 [161]3 years ago
5 0

Answer:

The correct answer to the following question will be MAC Address.

Explanation:

MAC Address: MAC (Media Access Control) Address, is an address that uniquely identifies every device on the network. Each address is separated by a colon and consists of six sets of two-two character.

  • As we know, a switch collects all the information sent by a hub and transmits it to the designation but it takes a look at the MAC address of the source to see it is already in the address table or not.

leonid [27]3 years ago
3 0

Answer:

MAC Addresses (Destination and Source MAC address)

Explanation:

A switch has 3 primary functions:

  • Forward frames
  • Learn addresses
  • Avoid loops

An Ethernet frame has the header, data and trailer and there are two specific fields in the header that helps the switch to know where to send data in future transmissions.

  • destination MAC address
  • source MAC address

every Ethernet frame has this and when the frame hits a switch or any device, any device can look at it ( an Ethernet frame ) and know where it is suppose to go and where it came from.

Every switch has a MAC address table where it stores MAC addresses of different computers on the network.

Example:

When a PC1 sends a frame to PC2 through a switch, the switch looks at the header of the Ethernet frame for the source mac address and adds the source MAC address to its MAC address table and also the port that it came through.

simply put:

A switch looks at the source MAC address to see if it knows it already, if it does. Great! no need to add it again to it's address table.

If it doesn't, it adds it's source address and the port that the frame came from.

This basically how the switch populates its MAC address table.

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Write a function that reads from a file the name and the weight of each person in pounds and calculates the equivalent weight in
spayn [35]

Answer:

#include <iostream>

#include <fstream>

#include <iomanip>

using namespace std;

int main(){

   string name;

   double weightKg, weightPd;

   cout<< fixed << setprecision(2);

   fstream myFile("filename.txt");

   while (getline( myFlie, name, weightPd)){

       weightKg = weight * 0.453592;

       cout<< name << weightPd <<weightKg;

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   myFile.close();

}

Explanation:

The C++ source code reads in the content of a file that has a name and weight value in pounds and outputs the name, weight in pounds and the weight in kilograms.

3 0
3 years ago
What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C
Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80                                    

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100  -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70   -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice)  -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice  -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice  -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref)  -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80  -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20  -> This line adds 20 to the value of Cost  and assigns the result to Cost variable

End Subprogram  -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e.  Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80                              

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