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2 years ago

Where does the potential energy of rocket goes when it escape from the influence of the earth

1 answer:

6 0

The potential energy of a rocket increases when its escapes from the influence of the earth. It increases when it escapes the earth's boundary.

<h3>What is escape speed?</h3>

Escape velocity or escape speed is the minimum speed required for a free, non-propelled object to escape from the gravitational pull of the main body and reach an infinite distance from it in celestial physics.

It is commonly expressed as an ideal speed, neglecting atmospheric friction.

If a spacecraft is launched from the moon at the escape speed of the earth then the value of escape speed will be the difference in both the velocities.

An object's height above the zero position directly relates to its gravitational potential energy.

The kinetic energy of motion is converted into gravitational potential power as your rocket ascends.

The rocket possesses gravitational potential energy as it climbs because it is becoming farther away from the Earth's surface, much as a positive and negative charge moving apart.

The potential energy of a rocket increases when its escapes from the influence of the earth. It increases when it escapes the earth's boundary.

To learn more about the escape speed refer to the link;

brainly.com/question/14178880

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A 16 g piece of Styrofoam carries a net charge of -8.6 µC and floats above the center of a large horizontal sheet of plastic tha

PilotLPTM [1.2K]

Answer:

the charge per unit area on the plastic sheet is - 3.23 x 10⁻⁷ C/m²

Explanation:

given information:

styrofoam mass, m = 16 g = 0.016 kg

net charge, q = - 8.6 μC

to calculate the charge per unit area on the plastic sheet, we can use the following equation:

$F_{e} = mg$

where

$F_{e} =$ the force between the electric field

m = mass

g = gravitational force

$F_{e} =qE$

where

q = charge

E = electric field

and

E = σ/2ε₀

where

ε₀ = permitivity

thus

$F_{e} =qE$

mg = qσ/2ε₀

σ = (2mg ε₀)/q

= 2 (0.016) (9.8) (8.85 x 10⁻¹²)/( - 8.6 x 10⁻⁶)

= - 3.23 x 10⁻⁷ C/m²

8 0

4 years ago

Which of the following is an example of a chemical change?

ss7ja [257]

Answer:

Burning Paper

Explanation:

This is a chemical reaction, because new substances are formed

6 0

3 years ago

The time constant of an RC circuit is 2.7 s. How much time t is required for the capacitor (uncharged initially) to gain 0.63 of

gayaneshka [121]

Answer:

2.7s

Explanation:

The solution of time required is shown below:-

In the RC circuit condenser charge 63 percent of the full charge from initial time to constant time

Now, the

63% that is equal to 0.63 which is full equilibrium charge

Therefore, the time required to maintain will be Equal to time (t) constant that is 2.7s

So, the correct answer is 2.7s

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3 years ago

The Apollo Lunar Module was used to make the transition from the spacecraft to the Moon's surface and back. Consider a similar m

ivolga24 [154]

Answer:

v=6.05 m/s

Explanation:

Given that,

Th initial velocity of the lander, u = 1.2 m/s

The lander is at a height of 1.8 m, d = 1.8 m

We need to find the velocity of the lander at impact. It is a concept based on the conservation of mechanical energy. So,

$\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2=W\\\\\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2=F\times d\\\\\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2=mgd\\\\\dfrac{1}{2}m(v^2-u^2)=mgd\\\\v^2-u^2=2gd$

v is the velocity of the lander at the impact

g is the acceleration due to gravity on the surface of Mars, which is 0.4 times that on the surface of the Earth, g = 0.4 × 9.8 = 3.92 m/s²

So,

$v=\sqrt{u^2+2gd} \\\\v=\sqrt{(1.2)^2+2\times 9.8\times 1.8} \\\\v=6.05\ m/s$

So, the velocity of the lander at the impact is 6.05 m/s.

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3 years ago

A firefighter directs a stream of water from a fire hose at an angle of 40.0° above the horizontal. If the velocity of the strea

mina [271]

Answer: The time of motion of the stream of water is calculated as follows;

X = Vₓt

Explanation:

5 0

2 years ago