The magnetic field at the center of the arc is 4 × 10^(-4) T.
To find the answer, we need to know about the magnetic field due to a circular arc.
<h3>What's the mathematical expression of magnetic field at the center of a circular arc?</h3>
- According to Biot savert's law, magnetic field at the center of a circular arc is
- B=(μ₀ I/4π)× (arc/radius²)
- As arc is given as angle × radius, so
B=( μ₀I/4π)×(angle/radius)
<h3>What will be the magnetic field at the center of a circular arc, if the arc has current 26.9 A, radius 0.6 cm and angle 0.9 radian?</h3>
B=(μ₀ I/4π)× (0.9/0.006)
= (10^(-7)× 26.9)× (0.9/0.006)
= 4 × 10^(-4) T
Thus, we can conclude that the magnitude of magnetic field at the center of the circular arc is 4 × 10^(-4) T.
Learn more about the magnetic field of a circular arc here:
brainly.com/question/15259752
#SPJ4
Explanation:
here,load=100N
effort=200N
distance travelled by load=2cm
distance travelled by effort=10cm
Now, output work=L*Ld
=100*2
=200g
Again,
input work =E*Ed
200*10
2000j
again, efficiency = output work/input work*100%
200/2000*100%
=10%
please don't forget to write symbol
The best and most correct answer among the choices provided by the question is the first choice "sodium nitrate"
<span>Sodium nitrate is the chemical compound with the formula NaNO₃. This alkali metal nitrate salt is also known as Chile saltpeter or Peru saltpeter to distinguish it from ordinary saltpeter, potassium nitrate.</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Depends on how steep the roof is , maybe the egg will just stay where it is but if the roof is more to the left it will fall to the left and same goes for right !
I think the answer is wind
