Well you can automatically eliminate, A, because when you multiply one number that's positive and another number that's negative the result is always going to be negative.
However, when you multiply two negatives the result is always positive!
So, the only ones up there that would result in a positive number is B and C
***D. was not posted so I cannot determine that one!
Answer:
77.75%
Step-by-step explanation:
We just have to find the sums of the product of Joey's averages and their contribution to the total grade.
Test: 0.45 * 0.8 = 0.36 = 36%
Quizzes: 0.3 * 0.85 = 0.255 = 25.5%
Homework: 0.25 * 0.65 = 0.1625 = 16.25%
Total: 36% + 25.5% + 16.25% = 77.75%
Answer:
B
Step-by-step explanation:
31-23=8
41-31=10
53-41=12
So next number should be 53+14, that is 67.
Follow the rule:
67+16=83
83+18=101
Draw the triangle and then use Pythagoras' theorem
distance =
![\sqrt{18 ^{2} +8 ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B18%20%5E%7B2%7D%20%2B8%20%5E%7B2%7D%20%20%20%7D%20)
= 19.70 (2dp)
Answer:
The width of the window should be
and the height of the window should be ![3.8\ ft](https://tex.z-dn.net/?f=3.8%5C%20ft)
Step-by-step explanation:
we know that
The circumference of a semicircle (window) is equal to
![C=\pi r](https://tex.z-dn.net/?f=C%3D%5Cpi%20r)
we have that
![C=12\ ft](https://tex.z-dn.net/?f=C%3D12%5C%20ft)
![\pi=3.14](https://tex.z-dn.net/?f=%5Cpi%3D3.14)
substitute and solve for r
![12=(3.14)r](https://tex.z-dn.net/?f=12%3D%283.14%29r)
![r=12/3.14=3.8\ ft](https://tex.z-dn.net/?f=r%3D12%2F3.14%3D3.8%5C%20ft)
so
the width of the window is equal to the diameter of the semicircle
so
The width of the window should be
and the height of the window should be ![3.8\ ft](https://tex.z-dn.net/?f=3.8%5C%20ft)