Substituting the value of X in each of the equations.The best answer would be the equation satisfying both of the sides.
Therefore,
Substituting the values in the second equation gives the best answer.
8(1.2)^2 + 34 = 45.52 centimeters
Answer:
It seems that you have missed to upload the shaded region for this problem. you are requested to please provide the shaded region so that we can help you with this problem
Step-by-step explanation:
Answer:
2/-5
Step-by-step explanation:
(-2) - (-4) = 2
(-6) - (-1) = -5
Answer: 100 miles
Step-by-step explanation: How much time does the bird spend in flight? If you represent the problem in terms of the amount of time the bird is flying, then a solution is fairly straightforward. The two trains are 50 miles apart, and are approaching each other at a relative speed of 50 mph (25 + 25), so it will take one hour for them to meet. If the bird spends one hour flying at 100 mph, then it will traverse 100 miles before the trains meet.
Answer: 0.025
Step-by-step explanation:
Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].
The probability density function :-
Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-
![\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025](https://tex.z-dn.net/?f=%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20f%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20%5Cdfrac%7B1%7D%7B10%7D%5C%20dx%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%7Cx%7C%5E%7B50.5%7D_%7B50.25%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%5C%20%5B50.5-50.25%5D%3D%5Cdfrac%7B1%7D%7B10%7D%5Ctimes%280.25%29%3D0.025)
Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025
Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025
