Answer:
B
Step-by-step explanation:
If you plug in -9 you will get -11 for both side.
Step-by-step explanation:
<u>Step 1: Substitute x from the second equation into the second one</u>
<u>Step 2: Substitute y into the second equation</u>
Answer:
Answer:
Step-by-step explanation:
6 - 3(x + 1) = 18 ⇔ 3 - 3x = 18 ⇒ <em>x = 5</em>
y - 6 = 17 ⇒ <em>y = 23</em>
z - 3 = 4z ⇒ <em>z = - 1</em>
18 - 3(0) = 9w ⇒ <em>w = 2</em>
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I'm going to solve for you some another question you asked, I did not see the right answer... :)
There are two scenarios, because the expression under the module can be positive and can be negative: | 3x + 2| - 2 > 3 ⇔ | 3x + 2| > 5
<em>(1).</em> If <u><em>(3x + 2) is positive</em></u> then
3x + 2 > 5 ⇒ <em>x > 3</em>
<em>(2).</em> If <u><em>(3x + 2) is negative</em></u> then
- (3x + 2) > 5
- 3x - 2 > 5
- 3x > 7 ⇒ x < -
The final answer is <em>x < - 2.3 or x > 1</em>
describes a sum of the areas of 50 rectangles, each of width
, and the
th rectangle has height
.
ranges from a small positive number to 1, which means the integration interval must be
. The sum is then the right-endpoint Riemann sum of
over the interval with
equally spaced subintervals, so
The sum itself evaluates to roughly 0.676, while the exact value of the integral is
.