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jekas [21]
4 years ago
6

Mrs. larnell is making snack packs for a class picnic. She puts 1/4 pound of apples, 1/8 pound of nut mix, and 1/16 pound of cho

colate in each students pack. there are 24 students in the class. What is the total weight of the snack packs? Is there mor than one way to solve this problem?
hint: adding and multiplying is what you do in this problem.


PLEASE HELP!
Mathematics
1 answer:
katrin [286]4 years ago
7 0
(1/4+1/8+1/16)×24=(7/16)×24=10.5
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4 0
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wo mechanics worked on a car. The first mechanic charged $95 per hour, and the second mechanic charged $75per hour. The mechanic
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5 hours and 25 minutes I think (Im not sure)

8 0
2 years ago
Read 2 more answers
Can y'all help me with number 6.
Juliette [100K]
SOH CAH TOA -> \bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}

so.. which of those fellows do we use?
well, the triangle gives us

the angle, 15 degrees, for elevation angle
the adjacent side, 50m
and we want the opposite side, the slide

so...who has only, the angle, opposite, and adjacent sides?
well, low and behold, is Ms tangent
thus
\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad 
\begin{cases}
\theta\to 15^o\\
adjacent=50\\
opposite=x-15
\end{cases}
\\ \quad \\
tan(15^o)=\cfrac{x-15}{50}\implies 50tan(15^o)=x-15\\\\ 50\cdot tan(15^o)+15=x

notice, "x" in the picture, is the distance from the ground up to the top of the waterslide, using that triangle, what we're getting is just the distance, from the shorter slide, to the taller one, or x - 15
thus, the opposite side is x -15

6 0
3 years ago
Calculate the distance between the points F=(-2,1) and A=(4,-2) in the coordinate plane. Round your answer to the nearest hundre
Anton [14]

Answer:

The distance between F and A is approximately 6.71 units.

Step-by-step explanation:

To find the distance between any two points, we can consider using the distance formula. Recall that:

\displaystyle d  = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let F(-2, 1) be (<em>x</em>₁, <em>y</em>₁) and A(4, -2) be (<em>x</em>₂, <em>y</em>₂).

Substitute and evaluate:

\displaystyle \begin{aligned} FA &= \sqrt{((4) - (-2))^2 + ((-2) - (1)^2} \\ \\&=\sqrt{(6)^2 + (-3)^2} \\ \\&=\sqrt{36 + 9} \\ \\ &= \sqrt{45} \\ \\ &= 3\sqrt{5}\\ \\&\approx 6.71\text{ units}  \end{aligned}

In conclusion, the distance between <em>F</em> and <em>A</em> is approximately 6.71 units.

8 0
3 years ago
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