Answer:
ummm
Step-by-step explanation:
6185152673 For the second question and 0/0 is unknown for now
Option C
For each value of y, -2 is a solution of -21 = 6y - 9
<u>Solution:</u>
Given, equation is – 21 = 6y – 9
We have to find that whether given set of options can satisfy the above equation or not
Now, let us check one by one option
<em><u>Option A) </u></em>
Given option is -5
Let us substitute -5 in given equation
- 21 = 6(-5) – 9
- 21 = -30 – 9
- 21 = - 39
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option B)</u></em>
Given option is 3
- 21 = 6(3) – 9
- 21 = 18 – 9
- 21 = 9
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option C)</u></em>
Given option is -2
- 21 = 6(-2) – 9
- 21 = - 12 – 9
- 21 = - 21
L.H.S = R.H.S ⇒ yes a solution
<em><u>Option D)</u></em>
- 21 = 6(9) – 9
- 21 = 54 – 9
- 21 = 45
L.H.S ≠ R.H.S ⇒ not a solution
Hence, the solution for the given equation is – 2, so option c is correct
Answer:
Step-by-step explanation:
Remark
You have 2 points to solve the equation y = mx + b. After finding m, use either of the points to find b.
Formula
y = mx + b
m = (y2 - y1)/(x2 - x1)
Solution
- y2 = 13
- y1 = 5
- x2 = 0
- x1 = 24
m = (13 - 5)/(0 - 24)
m = 8 / - 24
m = - 1/3
y = mx + b
y = -1/3 x + b
Use (0,13) as the point.
13 = -1/3 * 0 + b
13 = b
The y intercept = (0,13)
The plot that organizes the data into 4 groups of equal sizes is box and whisker plot.
The image below shows a box and whisker plot. Following are the elements of box and whisker plot:
Minimum = This is the smallest value of the data set
Q1 = First (Lower) Quartile of the data set. 25% of the data values lie below this point
Q2 = Second Quartile or Median. This is the central value so 50% of the data values lie below this point
Q3 = Third (Upper) Quartile of the data set. 75% of the data values lie below this point.
Maximum = This is the maximum value of the data set.
Based on box and whisker plot we can compare two or more sets of data by comparing the spread of the data. We can also directly observe from the box and whisker plot if the data is uniform, normal or skewed. Using box and whisker plot we can also visualize any outliers that may be in the data.
