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2 years ago

Cotpheta•sin2pheta=1+cos2pheta1+cospheta1+sin2pheta

Mathematics

1 answer:

3241004551 [841]2 years ago

8 0

Answer:

Step-by-step explanation:

Did you mean.

$= \cot( \theta) . \sin(2 \theta)$

$= \frac{ \cos( \theta) }{ \sin( \theta) } .(2 \sin( \theta) \cos( \theta) )$

$= \frac{2 \sin( \theta) \cos {}^{2} ( \theta) }{ \sin( \theta) }$

$= 2 \cos {}^{2} ( \theta)$

$= 2.(1 - \sin {}^{2} ( \theta) )$

$= 2 - 2 \sin {}^{2} ( \theta)$

No option Solution.

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We can see that both terms with the same variable are separated, so let us manoeuvre so that they can be together on the same side of the equation.

To do that let us subtract 3x in the left side of our equation in order to cancel the original 3x in there, and do the same to the right side of the equation by the virtue of the general rule we talked about earlier. Now we have an equation that looks like this:

$3x-2-3x=5x-12-3x$

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Therefore the value of our x is 5.

Therefore the answer to our question is LETTER A. The solution set is {5}.

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1 year ago

Cotpheta•sin2pheta=1+cos2pheta1+cospheta1+sin2pheta ​

Cotpheta•sin2pheta=1+cos2pheta1+cospheta1+sin2pheta