1.25j+5.25 would be the answer. just combine like terms
Answer:
-63
Step-by-step explanation:
C=2 times j
c=2j
o=j-6
c+j+o=58
subsitte j-6 for o and 2j for c
2j+j+j-6=58
4j-6=58
add 6 to both sides
4j=64
divide both sides by 4
j=16
sub back
c=2j
c=2(16)
c=32
o=j-6
o=16-6
o=10
curtis=32
olivia=10
jonathan=16
equations are
c+j+o=58
c=2j
o=j-6
Hi there!
We know that the formula for the area of a rectangle is height * width. Thus, we can multiply these two expressions together:
![2x^4\cdot (x^2+8x+15)\\](https://tex.z-dn.net/?f=2x%5E4%5Ccdot%20%28x%5E2%2B8x%2B15%29%5C%5C)
Now, we know through the distributive property that we can distribute the
to everything in the parenthesis. Once this is done, we get:
![2x^4 \cdot x^2+2x^4\cdot8x+2x^4\cdot15](https://tex.z-dn.net/?f=2x%5E4%20%5Ccdot%20x%5E2%2B2x%5E4%5Ccdot8x%2B2x%5E4%5Ccdot15)
Now, we know through the power rule that when two exponents are multiplied together with the same base, the exponent can be added together
. This then would make our equation:
![2x^{4+2}+16x^{4+1}+30x^4\\](https://tex.z-dn.net/?f=2x%5E%7B4%2B2%7D%2B16x%5E%7B4%2B1%7D%2B30x%5E4%5C%5C)
Giving us for our final answer:
![2x^{6}+16x^{5}+30x^4\\](https://tex.z-dn.net/?f=2x%5E%7B6%7D%2B16x%5E%7B5%7D%2B30x%5E4%5C%5C)
Hope this helps!