Answer:

Step-by-step explanation:
Let 
![m=(y^3)^{\frac{1}{2}}\\\\m=y^{3\times \frac{1}{2}}\ \ \ \ \ \ \ \ \ [as\ (x^a)^b=x^{ab}]\\\\m=y^{\frac{3}{2}](https://tex.z-dn.net/?f=m%3D%28y%5E3%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cm%3Dy%5E%7B3%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%7D%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5Bas%5C%20%28x%5Ea%29%5Eb%3Dx%5E%7Bab%7D%5D%5C%5C%5C%5Cm%3Dy%5E%7B%5Cfrac%7B3%7D%7B2%7D)
Answer:
Using c++
Check the image for colors.
Step-by-step explanation:
#include <iostream>
using namespace std;
int main()
{
float length1,length2,width1,width2,area1,area2;
cout<<"length of Rectangle 1\n";
cin>>length1;
cout<<"\nwidth of Rectangle 1\n";
cin>>width1;
cout<<"\nlenght of Rectangle 2\n";
cin>>length2;
cout<<"\nwidth of Rectangle 2\n";
cin>>width2;
area1=length1*width1;
area2=length2*width2;
if (area1<area2)
{cout << "\nRectangle 2 has greater area";}
else {
if (area1>area2)
{cout << "\nRectangle 1 has greater area";}
else {cout << "\nAreas are the same";}
}
return 0;
}
Answer:
Step-by-step explanation:
f(x) = 3x + 1 and g(x) = x^2 - 6
(f + g) (x)
(3x + 1) + (x^2 - 6)
3x + 1 + x^2 - 6
3x - 5 - x^2
=> -x^2 + 3x - 5
I hope this helps!
D. <span>Colby and Sarah sold newspapers this past summer. Colby earned $4.50 for each newspaper he sold. Sarah's earnings were $35 less than Colby's at the end of the summer. The following expression shows Sarah's earnings:
4.50y − 35</span>