Question

The term can also be written as:

Answer 1

The correct expansion is the one in option b:

$Log_9(\frac{6}{11}) = Log_9(6) - Log_9(11)$

How to rewrite the term?

Here we must use the logarithmic property:

$Log(a) -Log(b) = Log(\frac{a}{b})$

Our expression in this case is:

$Log_9(\frac{6}{11})$

Using the above property, we can rewrite the expression as:

$Log_9(\frac{6}{11}) = Log_9(6) - Log_9(11)$

From this, we conclude that the correct option is B.

If you want to learn more about logarithms:

brainly.com/question/13473114

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