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Anton [14]
3 years ago
8

Ming won 121 lollipops playing

Mathematics
1 answer:
blagie [28]3 years ago
5 0
She has 28 left. if you subtract 121-9= 112 and 112/4 is 28
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Find the exact value of s in the given interval that has the given circular function value.
docker41 [41]

Answer:

\displaystyle s=\frac{3\pi}{4}

Step-by-step explanation:

<u>Trigonometric Values</u>

We need to find the angle s in the interval [π/2,π] where:

\displaystyle \sin s=\frac{\sqrt{2}}{2}

There are two possible angles that have the same sine value in the first rotation of s. Any angle on the first quadrant has the same sine as its supplementary angle in the second quadrant.

The first angle s whose sine is \frac{\sqrt{2}}{2} is:

\displaystyle s=\frac{\pi }{4}

The other angle is its supplementary angle:

\displaystyle s=\pi-\frac{\pi }{4}=\frac{3\pi}{4}

Only this last angle lies on the required interval, thus:

\boxed{\displaystyle s=\frac{3\pi}{4}}

8 0
3 years ago
Find the GCF of the terms of the polynomial. 18x4 – 27x3 – 36x2
d1i1m1o1n [39]

Answer:

9 x^ 2

Step-by-step explanation:

18x4 – 27x3 – 36x2

<u>GCF :</u>

<em>Find the prime factors of each term in order to find the greatest common factor (GCF)</em>

= 9 x^ 2

3 0
4 years ago
For a circle of radius 5 feet, find the arc length s subtended by a central angle of 42 degress
MrMuchimi
\bf \textit{arc's length}\\\\&#10;s=\cfrac{\theta r\pi }{180}\quad &#10;\begin{cases}&#10;r=radius\\&#10;\theta = angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;r=5\\&#10;\theta = 42&#10;\end{cases}\implies s=\cfrac{42\cdot 5\cdot \pi }{180}
4 0
4 years ago
Read 2 more answers
8 friends share 4 sheets of construction paper equally how much does each person get
igor_vitrenko [27]
Each friend gets half a piece of construction paper
8 0
3 years ago
Read 2 more answers
In ΔXYZ, ∠Y is a right angle and sin X = 12/25 Find sec X, tan X, and cos Z in fraction and in decimal form. Round to the neares
Bezzdna [24]

Answer:

<u>In ΔXYZ</u>

  • ∠Y is a right angle
  • ∠X and ∠Z are complementary angles
  • sin X = 12/25

-------------

  • sec X = 1/cos X =  1/\sqrt{1- sin^2X}  = 1/\sqrt{1 - 12^2/25^2} = 1/\sqrt{481}/25 = 25/\sqrt{481}
  • tan X = sin X / cos X = 12/{25 :  {\sqrt{481} }/25 = 12/{\sqrt{481} }
  • cos Z = sin X = 12/25
6 0
3 years ago
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