Hello.
TP is a molecule with adenosine and three phosphate groups attached to it (adenosine triphosphate). To get energy from ATP, one of the bonds between the phosphates is broken, yielding energy and the molecule ADP - adenosine diphosphate, a molecule with adenosine and two phosphates.
<span>In order to 'recharge' the molecule, a phosphate group is re-attached to ADP by ATP-synthase to yield ATP. In other words, energy is stored in the bonds between phosphates, and breaking the bond releases that energy.
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Have a nice day
Answer:
The compound is dissolved in water
Explanation:
"aq." is the abbreviation for "aqueous" ( watery).
In chemical equations the symbol (aq) means that the substance is dissolved in water.
Reduce osteoblast activity while boosting osteoclast activity
osteoblast:
- Untreated celiac disease has a number of potential side effects, including the failure for children to reach their ideal bone density and adult bone loss, both of which raise the risk of osteoporosis. Following a gluten-free diet is the only way to treat celiac disease.
- As a result, celiac disease is common in both children and adults with low bone density. When celiac disease is discovered in an adult, the risk of osteoporosis is very significant (because they have gone longer without absorbing enough calcium and other nutrients).
- Osteoporosis is a bone disease that appears when bone mass, bone mineral density, or both drop or when the quality or structure of the bone deteriorates. This may result in a loss of bone density and an elevated risk of fractures (broken bones).
Learn more about osteoporosis here brainly.com/question/14601010
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<span>Bacterial genome is prone to mutational changes due to its simple nature and less efficient DNA repair mechanisms compared to humans, thus it has more chances of obtaining new genetic traits.</span>
Answer:
In order to find average speed during each interval, we need to divide the distance during those intervals with the period of time. So, for the first interval (day 0 to day 2) hawksbill started from 0 and reached 10 kilometers by the end of the second day. That means that it crossed 10 kilometers in 2 days, so the average speed is 10/2 which is 5 km/day. Similarly, we can calculate speed for other intervals:
• day 2 - day 3: it went from 10 to 12 km in one day, which means it crossed 2 km in one day, so the average speed is 2/1 = 2 km/day
• day 3 - day 4: at the end of the third day it reached 12 km and at the end of the day 4 it remained at 12 km. That means the hawksbill wasn't moving in that interval so the speed was 0
• day 4 - day 5: it went from 12 km to 18 km, which means it crossed 18-12=6 km in one day, so the average speed is 6/1=6 km/day
• day 5 - day 6: it went from 18 to 24 km, which means it crossed 24-18=6 km in one day, so the speed was 6/1=6 km/day
So, to summarize, during the first interval turtle was moving with average speed of 5 km/day, then 2 km/day, in the third interval it wasn't moving and in the last two intervals, it moved in average speed of 6 km/day.
