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RUDIKE [14]
2 years ago
5

The gas exchange during cellular respiration involves _____ moving into cells and ____ moving out of cells. The gas exchange dur

ing cellular respiration involves _____ moving into cells and ____ moving out of cells. methane; nitrous oxide nitrous oxide; oxygen oxygen; carbon dioxide carbon dioxide; oxygen
Biology
2 answers:
damaskus [11]2 years ago
8 0

Answer:

The gas exchange during cellular respiration involves oxygen moving into cells and carbon dioxide moving out of cells.

Explanation:

"...the process by which organisms combine oxygen with foodstuff molecules, diverging the chemical energy in these substances into life-sustaining activities and discarding, as waste products, carbon dioxide and water." - Britannica

ludmilkaskok [199]2 years ago
6 0

The gas exchange during cellular respiration involves oxygen moving into cells and carbon dioxide moving out of cells.

During gas change oxygen actions from the lungs to the bloodstream. on an equal time, carbon dioxide passes from the blood to the lungs. This happens within the lungs among the alveoli and a network of tiny blood vessels known as capillaries, which might be located in the walls of the alveoli.

Three strategies are critical for the switch of oxygen from the out of doors air to the blood flowing through the lungs: airflow, diffusion, and perfusion. ventilation is the manner through which air moves in and out of the lungs.

The lungs and respiratory system permit us to respire. they create oxygen into our bodies (called a concept, or inhalation) and send carbon dioxide out (referred to as expiration, or exhalation). This alternate of oxygen and carbon dioxide is referred to as respiratory.

Learn more about the gas exchange here brainly.com/question/15423560

#SPJ4

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A cell consists of three parts: the cell membrane, the nucleus, and, between the two, the cytoplasm. so i would say one of those.
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3 years ago
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A group of students is trying to grow a kelp plant in a tank without any others animals. They use a temperature regulation syste
mina [271]

I have read the question several times and I believe "A.The kelp draws nutrients from the water rather than the soil, which it does not have available." would be your answer.

Although it is true that kelp is temperature sensitive, the question states that "They use a temperature regulation system to keep the water temperature at about 12°C." So even with the added addition of sunlight, I think the temperature still stays generally the same. And as long as the temperature is between 5-20 C degrees, the kelp should be okay.

However, kelp does not work the same as most land plants, kelp does not have a root system. It instead has a "holdfast" anchoring system that does not transport nutrients. So how does kelp get nutrients? From the water directly. Since the question says nothing about nutrients in the water, and directly talks about nutrients in the soil, we can assume that their is no nutrients in the water (only in the soil). Making A our answer.

This is a copy/pasted answer from a question I also answered.

brainly.com/question/4540702

3 0
3 years ago
Darker skin in equatorial environments is adaptive because it prevents ____________ deficiencies, which cause _____________ in n
Delicious77 [7]

Answer:

Vitamin D

Rickets

Explanation:

Lack of vitamin D causes rickets

3 0
3 years ago
Peter is burning fossil fuels as he uses the lawnmower. Which greenhouse gases is he generating?
Strike441 [17]

Answer:

carbon dioxide and methane

<u>OAmalOHopeO</u>

5 0
3 years ago
- 4x + 5y = - 36<br>15x – 3y = 32​
Aleonysh [2.5K]

Answer:

x=6/7, y=-228/35

Explanation:

-4x+5y = -36 /*3

15x-3y = 32  /*5

------------------------- here we multiply both equations to get common y

-12x+15y = -108

75x-15y = 160

------------------------- then we add these two equations to eliminate the y

-12x+75x+15y-15y = 54

63x = 54

------------------------- then we get the x

x = 54/63

x = 6/7 (after we divide both with 9)

------------------------ next up, we add the value of x in first equation

-4 * 6/7 + 5y = -36

-24/7 + 5y = -36

------------------------ we leave 5y on the left side

5y = -36 + 24/7

5y = -252/7 + 24/7

-------------------------- common divider is 7 so we multiply 36*7=252

5y = -228/7

y= -228/7/5/1

------------------------- now we leave only y on the left side

y = -228*1/7*5

y = -228/35

------------------------- when dividing the fragment we multiply outer and inner

6 0
3 years ago
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