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maxonik [38]
2 years ago
10

What is 3÷11= A. 11/3 B. 3/11 C. 3/8 D. 8/3

Mathematics
2 answers:
Semmy [17]2 years ago
4 0

Answer:

my answer is B. 3/11

Step-by-step explanation:

which is =27.27%

pls if correct please mark me as Brainliest Answer please

Katen [24]2 years ago
3 0

Answer:

B. 3/11

Step-by-step explanation:

the division symbol: ÷ essentially is the same as /

if you replace ÷ with / its the same thing.

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Choose the answer.
myrzilka [38]
**4/5** is equal to .8, so 4/5 is the answer. to check, multiply .8 x 5 = 4
4 0
3 years ago
Read 2 more answers
The quadrilaterals ABCD and PQRS are similar. Find the length X of SP.
BaLLatris [955]

Answer:

x = 3.6

Step-by-step explanation:

Since Quadrilateral ABCD ~ PQRS, therefore:

\frac{AB}{PQ} = \frac{BC}{QR} = \frac{CD}{RS} = \frac{DA}{SP}

Let's find the value of x by using the ratio of two corresponding sides of both quadrilaterals. Let's use:

\frac{CD}{RS} = \frac{DA}{SP}

CD = 5

RS = 4.5

DA = 4

SP = x

\frac{5}{4.5} = \frac{4}{x}

Cross multiply

5*x = 4.5*4

5x = 18

Divide both sides by 5

x = \frac{18}{5}

x = 3.6

6 0
3 years ago
Solve inequality 6y+5>8
ryzh [129]
6y + 5 > 8
6y> 8-5
6y> 3
y>3/6
Thus, y>1/2

5 0
4 years ago
Read 2 more answers
a car needs fixing and Abe can fix it for $70 per hour with a $60 part, but Gabe can fix it for $80 an hour with a $40 part. How
Nat2105 [25]

After 2 hours time ,  both Abe and Gabe to cost the same amount .

<u>Step-by-step explanation:</u>

Here we have , a car needs fixing and Abe can fix it for $70 per hour with a $60 part, but Gabe can fix it for $80 an hour with a $40 part. We need to find How long will it take for both Abe and Gabe to cost the same amount .Let's find out:

Let the time for which both Abe and Gabe to cost the same amount be x hours, so according to question scenario we will have equation as :

⇒ 70x+60=80x+40

⇒ (70x+60)-70x=(80x+40)-70x

⇒ 60=(10x+40)

⇒ 60-40=(10x+40)-40

⇒ 20=10x

⇒ x=2

Therefore , After 2 hours time ,  both Abe and Gabe to cost the same amount .

6 0
3 years ago
What is the nth term rule of the quadratic sequence below? 4,15,30,49,72,99,130,...
navik [9.2K]

Answer:

The nth term rule of the quadratic sequence is 2n^{2} +5n-3.

Step-by-step explanation:

We are given the following quadratic sequence below;

4, 15, 30, 49, 72, 99, 130,...

As we know that the formula for the nth term of the quadratic sequence is given by =  an^{2}+bn+c

Firstly, we will find the difference between the term of the given sequence;

1st difference of the given sequence;

(2nd term - 1st term), (3rd term - 2nd term), (4th term - 3rd term), (5th term - 4th term), (6th term - 5th term), (7th term - 6th term)

= (15 - 4), (30 - 15), (49 - 30), (72 - 49), (99 - 72), (130 - 99),....

= (11, 15, 19, 23, 27, 31,.....)

Now, we will find the second difference of the given sequence, i.e;

= (15 - 11), (19 - 15), (23 - 19), (27 - 23), (31 - 27),....

= (4, 4, 4, 4, 4)

Since the differences are same now, so to find the value of a we have to divide the value of second difference by 2, i.e;

The value of a  =  \dfrac{4}{2} = 2

SO, the first term of the nth term rule equation is an^{2} = 2n^{2}.

Now, in the term 2n^{2}, put the value of n = 1, 2, 3, 4 and 5 and then form the sequence, i.e;

If n = 1, then 2n^{2} = 2 \times (1)^{2} = 2

If n = 2, then 2n^{2} = 2 \times (2)^{2} = 8

If n = 3, then 2n^{2} = 2 \times (3)^{2} = 18

If n = 4, then 2n^{2} = 2 \times (4)^{2} = 32

If n = 5, then 2n^{2} = 2 \times (5)^{2} = 50

SO, the sequence formed is (2, 8, 18, 32, 50).

Now, find the difference of this sequence and the original quadratic sequence, i.e;

= (4 - 2), (15 - 8), (30 - 18), (49 - 32), (72 - 50)

= (2, 7, 12, 17, 22)

Now, as we can see that the above sequence resembles the general form of (5n - 3) because:

If we put n = 1, then (5n - 3) = 5 - 3 = 2

If we put n = 2, then (5n - 3) = 10 - 3 = 7 and so on....

From this, we concluded that the value of b and c are 5 and (-3) respectively.

Hence, the nth term rule for the given quadratic sequence is 2n^{2} +5n-3.

7 0
3 years ago
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