Answer:
Are you trying to solve for x?
x= 13
just kick the 3 to the other side, so a negative 3 would become a positive 3:
x= 10 + 3
x= 13
You can also use cymath it gives you the answer and explanation.
Hope this helps.
Answer: The area is 13
ft^2 or 40.84 ft^2
Step-by-step explanation:
First find the area of the square and subtract it from the area of the circle.
The area of a square is one of the side length squared.
A= 6^2
A = 36
Now find the area of the whole circle.As it indicates that the diameter is 14ft and to find the area of a circle,we need square the radius and multiply it by pi.
Since the diameter is 14 divide it by 2 to find the radius. 14/2 = 7
A= 7^2*
A = 49
We will leave the area in terms of pi.
49
- 36 = 13
Answer: The parametric is being tested here is "p" (population proportion).
The hypothesis test is left-tailed.
Step-by-step explanation:
Given : The null and alternative hypotheses are

The parametric is being tested here is "p", where p stands for population proportion.
Also, the type of test depends on the alternative hypotheses.
Since the alternative hypotheses is left-tailed, so the hypothesis test is left-tailed.
Answer:
C 1055 04 cm
Step-by-step explanation:
We don't need to see the figure, since we know for sure the cone fits into the cylinder (smaller diameter and height).
So, we first need to calculate the volume of the cylinder, which is given by the formula:
VT = π * r² * h
VT = 3.14 * 5² * 16 = 3.14 * 400 = 1,256 cubic cm
Then we calculate the volume of the cone, which is given by:
VC = (π * r² * h)/3
VC = (3.14 * 4² * 12)/3 = (3.14 * 192)/3 = 200.96 cu cm
Then we calculate the void space left inside the cylinder by subtracting the volume of the cone from the volume of the cylinder:
NV = VT - VC = 1,256 - 200.96 = 1,055.04 cu cm
<h3>
Answer: Choice A</h3>
![x^2\left(\sqrt[4]{x^2}\right)](https://tex.z-dn.net/?f=x%5E2%5Cleft%28%5Csqrt%5B4%5D%7Bx%5E2%7D%5Cright%29)
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Explanation:
The fourth root of x is the same as x^(1/4)
I.e,
![\sqrt[4]{x} = x^{1/4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D%20%3D%20x%5E%7B1%2F4%7D)
The same applies to x^10 as well
![\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B10%7D%7D%20%3D%20%5Cleft%28x%5E%7B10%7D%5Cright%29%5E%7B1%2F4%7D)
Multiply the exponents 10 and 1/4 to get 10/4
![\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B10%7D%7D%20%3D%20%5Cleft%28x%5E%7B10%7D%5Cright%29%5E%7B1%2F4%7D%20%3D%20x%5E%7B10%2A1%2F4%7D%20%3D%20x%5E%7B10%2F4%7D)
![\sqrt[4]{x^{10}} = x^{10/4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B10%7D%7D%20%3D%20x%5E%7B10%2F4%7D)
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If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below
![x^{m/n} = x^a\sqrt[n]{x^b}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20x%5Ea%5Csqrt%5Bn%5D%7Bx%5Eb%7D)
The 'a' and 'b' are found through dividing m/n
m/n = a remainder b
'a' is the quotient, b is the remainder
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The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4
m/n = 10/4 = 2 remainder 2
We have a = 2 and b = 2
So
![x^{m/n} = x^a\sqrt[n]{x^b}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20x%5Ea%5Csqrt%5Bn%5D%7Bx%5Eb%7D)
turns into
![x^{10/4} = x^2\sqrt[4]{x^2}](https://tex.z-dn.net/?f=x%5E%7B10%2F4%7D%20%3D%20x%5E2%5Csqrt%5B4%5D%7Bx%5E2%7D)
which means
![\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B10%7D%7D%20%3D%20%7Bx%5E2%7D%20%5Csqrt%5B4%5D%7Bx%5E2%7D)