All categories

2 years ago

What is 3÷11= A. 11/3 B. 3/11 C. 3/8 D. 8/3

Mathematics

2 answers:

Semmy [17]2 years ago

4 0

Answer:

my answer is B. 3/11

Step-by-step explanation:

which is =27.27%

pls if correct please mark me as Brainliest Answer please

Katen [24]2 years ago

3 0

Answer:

B. 3/11

Step-by-step explanation:

the division symbol: ÷ essentially is the same as /

if you replace ÷ with / its the same thing.

You might be interested in

Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)

UkoKoshka [18]

Since the limit becomes the undetermined form

$\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}$

it means that both polynomials have a root at $x=1$ . So, we can fact both numerator and denominator:

$x^3-2x^2+3x-2 = (x-1)(x^2-x+2)$

$2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)$

So, the fraction becomes

$\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}$

Now, as x approaches 1, you have no problems anymore:

$\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}$

4 0

3 years ago

A rectangular pool has a length of

Sholpan [36]

P=(15x-2+4x+7)2=(19x+5)2=38x+10

8 0

2 years ago

Write the ratio as a fraction in lowest terms. Be sure to make necessary conversions:

agasfer [191]

Answer:12533

Step-by-step explanation:

4 0

2 years ago

If a solution has 24g of sugar in 130ml of water, what is its concentration?

Jobisdone [24]

Answer: concentration = 15.58%

Step-by-step explanation:

Given: mass of sugar = 24 g = 24 ml [ ∵ 1 g = 1 ml]

Volume of solution = Quantity of water + quantity of solute

= 130 +24 ml

= 154 ml

Concentration = $\dfrac{mass\ of\ solute}{Volume\ of\ solution}\times100$

$=\dfrac{24}{154}\times 100\\\\\approx15.58\%$

Hence, the concentration =15.58%

3 0

3 years ago

jeka94

Answer:

g(x)

because it is a quadratic equation it is mirrored the other one isn’t even a function

8 0

3 years ago