Question

a car needs fixing and Abe can fix it for $70 per hour with a $60 part, but Gabe can fix it for $80 an hour with a $40 part. How long will it take for both abe and Gabe to cost the same amount

Answer 1

After 2 hours time ,  both Abe and Gabe to cost the same amount .

Step-by-step explanation:

Here we have , a car needs fixing and Abe can fix it for $70 per hour with a $60 part, but Gabe can fix it for $80 an hour with a $40 part. We need to find How long will it take for both Abe and Gabe to cost the same amount .Let's find out:

Let the time for which both Abe and Gabe to cost the same amount be x hours, so according to question scenario we will have equation as :

⇒ $70x+60=80x+40$

⇒ $(70x+60)-70x=(80x+40)-70x$

⇒ $60=(10x+40)$

⇒ $60-40=(10x+40)-40$

⇒ $20=10x$

⇒ $x=2$

Therefore , After 2 hours time ,  both Abe and Gabe to cost the same amount .