Answer:
(a) yes, this protocol allows only serializable schedules for transactions as due to this the system maintains it's consistency. As in this protocol a unique transaction id is being assigned and with the help of that transaction id the system would be able to identify the process which has taken place in what particular order. For example, in case of bank transfers
balance = 1000 transaction id 100
write ADD 200 transaction id 101
write SUB 1100 transaction id 102
write ADD 900 transaction id 103
in here with the help of transaction id we can check which operation has happened in which order, if not then some operation will not happen like 102 immediately after 100 and skipping 101
(b) the modified version of this protocol would be to also consider the time of transaction and take this factor in the consideration
Equal sign (=)
hope so !!!
Answer:
Explanation:
temporal locality can be defined as: when a particular memory is referenced or accessed several times within a specific period of time. In the question, i think the variable that exhibit temporal locality are I, J and 0(all the variable). This is because the variable J and 0 are accessed several times within the loop. I would not have been part of it, but in the A[I][J]=B[I][0]+A[J][I], the variable "I" is also accessed in the addition. this is why it is part of the temporal locality.
Loop takes only positive numbers and terminates once it encounters a negative numbers.
Answer and Explanation:
Using javascript:
Var positiveInt= window.prompt("insert positive integer");
While(positiveInt>=0){
Alert("a positive integer");
Var positiveInt= window.prompt("insert positive integer");
}
Or we use the do...while loop
Var positiveInt= window.prompt("insert positive integer");
do{
Var positiveInt= window.prompt("insert positive integer");
}
While (positiveInt>=0);
The above program in javascript checks to see if the input number is negative or positive using the while loop condition and keeps executing with each input until it gets a negative input
Answer:
result=0;
for (i=lo ; i<=hi; i++){
result += i;
}
Explanation:
The question says result was declared but not initialized, so using result without initializing it to 0 would throw an error as result would be undefined and you can't add a number to undefined
Another way to do it to keep everything inside the loop would be
for (i=lo ; i<=hi; i++){
if (i==lo) result= 0;
result += i;
}
but this is impractical since it would add unnecesary operations in each cycle of the loop
