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3 years ago

15 = 3h-9 Please explain

Mathematics

2 answers:

Naddik [55]3 years ago

8 0

Answer:

This is your answer ☺️

Afina-wow [57]3 years ago

6 0

The answer is h=15+9/3=8

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3 years ago

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Simplify the expression: w2 + 7w2 + 8w - 5 + 9 - 2w2

ololo11 [35]

<h3> $6w^2 +8w +4$ is the simplified expression</h3>

<em><u>Solution:</u></em>

Given that,

We have to simplify

$w^2 + 7w^2 + 8w -5+9-2w^2$

We can simplify the above expression by combining the like terms

Like terms are terms that has same variable with same exponent and same or different coefficient

From given,

$w^2 + 7w^2 + 8w -5+9-2w^2$

Group the like terms

$w^2 + 7w^2 -2w^2 + 8w - 5+9\\\\Combine\ the\ like\ terms\\\\6w^2 +8w -5+9\\\\Combine\ the\ constants\\\\6w^2 +8w +4$

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3 years ago

The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10

Rama09 [41]

Answer:

a) $E(X) = 6.45$

b) $E(X^{2} )= 57.25$

c) $V(X) = 15.648$

d) E(3X + 2) = 21.35

e) $E(3X^{2} +2) = 173.75$

f) V(3X+2) = 140.832

g) E(X+1) = 7.45

h) V(X+1) = 15.648

Step-by-step explanation:

a) $E(X) = \sum xP(x)$

$E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45$

$E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\ E(X^{2} )= 57.25$

$V(X) = E(X^{2} ) - (E(X))^{2} \\V(X) = 57.25 - 6.45^{2} \\V(X) = 15.648$

$E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35$

$E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75$

$V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832$

$E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45$

$V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648$

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