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Arte-miy333 [17]
2 years ago
14

A cake shop bakes a variety of brownies. the top-selling brownies are ones with toppings of chocolate chip, walnuts, or both. a

customer enters the store. the probability that the customer will pick both toppings is 0.4. what is the probability that they will pick neither the chocolate chip nor the walnut toppings?
Mathematics
1 answer:
sesenic [268]2 years ago
6 0

The probability that they will pick neither the chocolate chip nor the walnut toppings is 0.3

We have

the total of all probabilities is 1.00, or 100%.

In the Venn diagram, we have the probabilities 0.2, 0.4 and 0.1; these sum to

0.2+0.4+0.1 = 0.6+0.1 = 0.7.

This leaves us 1.00-0.7 = 0.3 for the remaining probability of no toppings.

Learn more about Probability:

brainly.com/question/13604758

#SPJ4

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The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

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3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\&#10;3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\&#10;x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\hbox{add 12 to both sides} \\&#10;x=11
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Step-by-step explanation:

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