Answer:
Jay started with $148.5 and Kay with $24.75.
Step-by-step explanation:
With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:
J=6K, where
J is the money Jay had
K is the money Kay had
Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:
J-33=2(K+33)
Now, you can replace J=6K in this equation and solve for K:
6K-33=2K+66
6K-2K=66+33
4K=66
K=24.75
Then, you can replace the value of K in J=6K:
J=6*24.75
J=148.5
According to this, the answer is that Jay started with $148.5 and Kay with $24.75.
Answer:
B. (B P R O G)
Step-by-step explanation:
this answer includes the whole population of the sample space
Answer:
Step-by-step explanation:
2 * L + 2 * W = 68
2*L = 2* 9x = 9x + 9x
2*W = 2*8x = 8x + 8x
Since the perimeter is 68
9x + 9x + 8x + 8x = 68
Let's divide the shaded region into two areas:
area 1: x = 0 ---> x = 2
ares 2: x = 2 ---> x = 4
In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.
Area 1:
Area 2:
Therefore, the area of the shaded portion of the graph is
A = A1 + A2 = 5.34
Answer:
its between c or b
Step-by-step explanation:
I've done this test before
