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tresset_1 [31]
3 years ago
13

I need help with answering the following questions. :/ :)

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0

Answer:

  a) (0, ∞)

  b) (-∞, ∞)

  c) x = 0

Step-by-step explanation:

It helps to have some idea what the log function is.

__

a) The domain is all positive numbers: (0, ∞).

b) The range is all real numbers: (-∞, ∞). (The vertical translation downward by 5 units does not change that.)

c) There is a vertical asymptote where the argument of the log function is zero: at x=0.

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The value of the 4th term is 80. the sequence is being doubled each step what is the 7th term?
leva [86]
This is a geometric sequence with common ratio (r) = 2.
an = ar^(n - 1)
a4 = a(2)^(4 - 1) = a(2)^3 = 8a
8a = 80
a = 80/8 = 10

7th term (a7) = 10(2)^(7 - 1) = 10(2^6) = 10(64) = 640
8 0
3 years ago
How can I prove that
Citrus2011 [14]

I can prove by being smart then that if you tell me all the ansers

6 0
3 years ago
The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are
almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = <u><em>the number that are not correctly calibrated.</em></u>

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_3

So, the required probability = \frac{^{6}C_3}{^{8}C_3}  

                                              = \frac{20}{56}  = <u>0.35</u>

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_2

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_1

So, the required probability = \frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}  

                                                = \frac{30}{56}  = <u>0.54</u>

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_1

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_2

So, the required probability = \frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}  

                                                = \frac{6}{56}  = <u>0.11</u>

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0
3 years ago
True or False. To select 3 items out of 4 distinct objects, use C(4,3).
kenny6666 [7]

Answer:

True.

Step-by-step explanation:

C(4, 3) means the number of combinations from 4 items taking 3 at a time.  We are selecting 3 distinct items and it doesn't say anything about the order in which they are selected , so we use  a combination formula  not a permutation ( where order does matter).

C(4, 3)  = 4! / 3! 1!

= 4*3*2*1 / 3*2*1*1

= 4.

There are 4 ways to select 3 items from 4.

6 0
3 years ago
Isolate the variable on the following problem. show your work.<br><br>-2=-4+x​
blsea [12.9K]

Answer:

x=2

Step-by-step explanation:

Add 4 to both sides:

-2=-4+x​

-2+4=-4+4+x​

2=x

5 0
3 years ago
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