(1 point) A tank contains 50 kg of salt and 1000 L of
1 answer:
Your answers for (a) and (c) are correct.
(b) Salt flows into the tank at a rate of
If is the amount of salt (in kg) in the tank at time (in min), then the salt flows out of the tank at a rate of
The net rate of change in the amount of salt in the tank at any time is then governed by the linear differential equation
I'll solve this with the integrating factor method. The I.F. is
Distributing on both sides of the ODE gives
Integrate both sides.
Given that , we find
so that
Then the amount of salt in the tank after 1 hr = 60 min is
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<span>the answer is =<span><span><span>7/24</span></span><span></span></span></span>
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x<= 2
Step-by-step explanation:
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b=(r/5)-a
Step-by-step explanation:
To solve, you do the mathematics.
r=5(b+a)
r=5b+5a
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Fraction form: x > 1/4
Decimal form: x > 0.25
Step-by-step explanation: