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2 years ago

Someone please help 4(x-2)-3>-3(-2+6)+2

Mathematics

1 answer:

NNADVOKAT [17]2 years ago

5 0

Answer:

Fraction form: x > 1/4

Decimal form: x > 0.25

Step-by-step explanation:

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A piece of ribbon is 1 metre in length. Sasha cuts of some of the

Varvara68 [4.7K]

Answer:

high jatdog

Step-by-step explanation:

napaka pogi ko ayieeee

7 0

2 years ago

Which number line shows the correct locations of ALL the given values?

bija089 [108]

A is the only number line that correctly shows the locations of all given values.

Answer=A

***EDIT***

Okay, so if you look at the number line, you notice that the distance between one line and the next is equal to 1/4. When we move to the left, we decrease in value. When we move to the right, we increase in value.

So, knowing that, lets look at A and see if all of the numbers are correctly placed.

1/2 should be two lines to the right of 0 (since distance between one line and the next is equal to 1/4, and 1/4+1/4=2/4 or 1/2)

-4 is a relatively easy value to find, since its line is labeled.

-2 3/4 should be three lines to the right of -2 (since distance between one line and the next is equal to 1/4, and 1/4+1/4+1/4=3/4 and if you go 3/4 to the left of -2 u get -2 3/4)
(-2-3/4=-2 3/4)

1 1/4 should be three lines behind 2 (since distance between one line and the next is equal to 1/4, and 1/4+1/4+1/4=3/4 and if you go 3/4 to the left of 2 you get 1 1/4)
(2-3/4=1 1/4)

6 0

2 years ago

Find the integral <br> ∫√(9+x)/(9-x)

densk [106]

I suppose you mean

$\displaystyle \int \frac{\sqrt{9+x}}{9-x} \, dx$

Substitute y = √(9 + x). Solving for x gives x = y² - 9, so that 9 - x = 18 - y², and we have differential dx = 2y dy. Replacing everything in the integral gives

$\displaystyle \int \frac{2y^2}{18 - y^2} \, dy$

Simplify the integrand by dividing:

$\dfrac{2y^2}{18 - y^2} = -2 + \dfrac{36}{18 - y^2}$

$\implies \displaystyle \int \left(\frac{36}{18-y^2} - 2\right) \, dy$

For the first term of this new integral, we have the partial fraction expansion

$\dfrac1{18 - y^2} = \dfrac1{\sqrt{72}} \left(\dfrac1{\sqrt{18}-y} + \dfrac1{\sqrt{18}+y}\right)$

$\implies \displaystyle \frac{36}{\sqrt{72}} \int \left(\frac1{\sqrt{18}-y} + \frac1{\sqrt{18}+y}\right) \, dy - 2 \int dy$

The rest is trivial:

$\displaystyle \sqrt{18} \int \left(\frac1{\sqrt{18}-y} + \frac1{\sqrt{18}+y}\right) \, dy - 2 \int dy$

$= \displaystyle \sqrt{18} \left(\ln\left|\sqrt{18}+y\right| - \ln\left|\sqrt{18}-y\right|\right) - 2y + C$

$= \displaystyle \sqrt{18} \ln\left|\frac{\sqrt{18}+y}{\sqrt{18}-y}\right| - 2y + C$

$= \boxed{\displaystyle \sqrt{18} \ln\left|\frac{\sqrt{18}+\sqrt{9+x}}{\sqrt{18}-\sqrt{9+x}}\right| - 2\sqrt{9+x} + C}$

6 0

1 year ago

The Video Club charges a $100 membership fee and then charges $5 per movie. The Movie Market has a $25 membership fee and then c

cluponka [151]

Answer:

At 15 movies, both will cost $175

Step-by-step explanation:

Set it up algebraicly. Let x be the number of movies

100 + 5x = 25 + 10x

75 + 5x = 10x

75 = 5x

x = 15

Lets substitute x into one equation

100 + 5(15)

100+75

175

4 0

2 years ago

Which of the following functions is graphed below??

yawa3891 [41]

the answer is B or D. I mean both doesnt really matter which one. We can see that graph fallows cubic function pattern when x < 2 and option A is saying oposite (when x > 2). Option C cannot be the answer because there is graph when x is larger than 2 and that option doesnt define function when x is larger than 2.

So, B and D

4 0

2 years ago