Question

If f(a) = 2a ^ 3 + 3a ^ 2 + 5 , find f(- 2)

Answer 1

Answer: 1

Step-by-step explanation:

Just plug in -2 anywhere you see an a

$f(a)=2a^3+3a^2+5\\f(-2)=2(-2)^3+3(-2)^2+5\\f(-2)=2(-8)+12+5\\f(-2)=-16+12+5\\f(-2)=1$

Answer 2

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Answer $\curvearrowright$

f(-2)=1

Step-by-step explanation $\curvearrowright$

Given,

• Original Expression = $\sf{f(a)=2a^3+3a^2+5}$

To find,

• f(-2) = ??

                                           All work is shown here. :))

$\Large\begin{gathered} \boldsymbol{\sf{Plug \ in \ the \ number \ for \ a, \ which \ is \ -2 (it's \ given \ to \ us). Then}}\\ \boldsymbol{\sf{evaluate,}} \\ \curvearrowright\\\boldsymbol{\sf{Now \ substitute \ -2}} \\\curvearrowright\\\sf{2(-2)^3+3(-2)^2+5}\\\sf{2*(-8)+3*4+5}\\\sf{}-16+12+5=-4+5}\\\underline{\boxed{\sf{f(-2)=1}}}\end{gathered}$

Done !!

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$\tiny\pmb{CALLIGRAPHY}$