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Solnce55 [7]
2 years ago
7

What is the solution to the equation 1/4x-1/8=7/8+1/2x?

Mathematics
2 answers:
julia-pushkina [17]2 years ago
6 0

Answer:

x=-1/4

Step-by-step explanation:

1 / 4x-1/8 = 7/8 + 1 / 2x <=> 1/4x - 1/2x = 7/8+1/8 <=> 1/4x-2/4x = 1  <=> -1/4x = 1

<=> x= -1/4

NISA [10]2 years ago
4 0

Answer:

2.7 + 8x/8.2

Step-by-step explanation:

1/4x - 1/8 = 7/8 + 1/2x x/4 - 1/8 = 7/8 + x/2

8x + 4 (-1)/4.8 = 2.7 + 8x/8.2

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Please help me with these calculus bc questions
zhannawk [14.2K]

4. Compute the derivative.

y = 2x^2 - x - 1 \implies \dfrac{dy}{dx} = 4x - 1

Find when the gradient is 7.

4x - 1 = 7 \implies 4x = 8 \implies x = 2

Evaluate y at this point.

y = 2\cdot2^2-2-1 = 5

The point we want is then (2, 5).

5. The curve crosses the x-axis when y=0. We have

y = \dfrac{x - 4}x = 1 - \dfrac4x = 0 \implies \dfrac4x = 1 \implies x = 4

Compute the derivative.

y = 1 - \dfrac4x \implies \dfrac{dy}{dx} = -\dfrac4{x^2}

At the point we want, the gradient is

\dfrac{dy}{dx}\bigg|_{x=4} = -\dfrac4{4^2} = \boxed{-\dfrac14}

6. The curve crosses the y-axis when x=0. Compute the derivative.

\dfrac{dy}{dx} = 3x^2 - 4x + 5

When x=0, the gradient is

\dfrac{dy}{dx}\bigg|_{x=0} = 3\cdot0^2 - 4\cdot0 + 5 = \boxed{5}

7. Set y=5 and solve for x. The curve and line meet when

5 = 2x^2 + 7x - 4 \implies 2x^2 + 7x - 9 = (x - 1)(2x+9) = 0 \implies x=1 \text{ or } x = -\dfrac92

Compute the derivative (for the curve) and evaluate it at these x values.

\dfrac{dy}{dx} = 4x + 7

\dfrac{dy}{dx}\bigg|_{x=1} = 4\cdot1+7 = \boxed{11}

\dfrac{dy}{dx}\bigg|_{x=-9/2} = 4\cdot\left(-\dfrac92\right)+7=\boxed{-11}

8. Compute the derivative.

y = ax^2 + bx \implies \dfrac{dy}{dx} = 2ax + b

The gradient is 8 when x=2, so

2a\cdot2 + b = 8 \implies 4a + b = 8

and the gradient is -10 when x=-1, so

2a\cdot(-1) + b = -10 \implies -2a + b = -10

Solve for a and b. Eliminating b, we have

(4a + b) - (-2a + b) = 8 - (-10) \implies 6a = 18 \implies \boxed{a=3}

so that

4\cdot3+b = 8 \implies 12 + b = 8 \implies \boxed{b = -4}.

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