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sammy [17]
3 years ago
9

1.What is the length of the altitude of an equilateral triangle with side lengths of 34 inches?

Mathematics
1 answer:
sweet [91]3 years ago
7 0

Answer:

Step-by-step explanation:

Remark

<u>Question One</u>

It's equilateral. All three sides are equal. The base is 34 as well. So two right angles can be formed on the base by dropping the altitude from the top vertex.

Givens

altitude = h

a = 34/2 = 17

hypotenuse = 34

Formula

a^2 + h^2 = c^2

Solution

17^2 + h^2 = 34^2

289 + h^2 = 1156

h^2 +289 =1156

h^2 = 1156 - 289

h^2 = 867

sqrt(h^2) = sqrt(867)

h = 29.444

==============

<u>Question Two</u>

Givens

b = 10 feet

c = ?

height = h = 16

Formula

c^2 = b^2 + h^2

Solution

c^2 = 10^2 + 16^2

c^2 = 100 + 256

c^2 = 356

sqrt(c^2) = sqrt(356)

c = 18.87

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Read 2 more answers
Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total
Katarina [22]

Answer:

t-shirts: 2790

profit: $12209

Step-by-step explanation:

Given  the function:

p(x) = -x³ + 4x² + x

we want to maximize it.

The following criteria must be satisfied at the maximum:

dp/dx = 0

d²p/dx² < 0

dp/dx = -3x² + 8x + 1 = 0

Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2 -4(a)(c)}}{2(a)}

x = \frac{-8 \pm \sqrt{8^2 -4(-3)(1)}}{2(-3)}

x = \frac{-8 \pm 8.72}{-6}

x_1 = \frac{-8 + 8.72}{-6}

x_1 = -0.12

x_2 = \frac{-8 - 8.72}{-6}

x_2 = 2.79

d²p/dx² = -6x + 8

d²p/dx² at x = -0.12: -6(-0.12) + 8 = 8.72 > 0

d²p/dx² at x = 2.79: -6(2.79) + 8 = -8.74 < 0

Then, he should prints 2.79 thousands, that is, 2790 t-shirts to make maximum profits.

Replacing into profit equation:

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that is, $12209

3 0
3 years ago
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