1.What is the length of the altitude of an equilateral triangle with side lengths of 34 inches?
1 answer:
Answer:
Step-by-step explanation:
Remark
<u>Question One </u>
It's equilateral. All three sides are equal. The base is 34 as well. So two right angles can be formed on the base by dropping the altitude from the top vertex.
Givens
altitude = h
a = 34/2 = 17
hypotenuse = 34
Formula
a^2 + h^2 = c^2
Solution
17^2 + h^2 = 34^2
289 + h^2 = 1156
h^2 +289 =1156
h^2 = 1156 - 289
h^2 = 867
sqrt(h^2) = sqrt(867)
h = 29.444
==============
<u>Question Two </u>
Givens
b = 10 feet
c = ?
height = h = 16
Formula
c^2 = b^2 + h^2
Solution
c^2 = 10^2 + 16^2
c^2 = 100 + 256
c^2 = 356
sqrt(c^2) = sqrt(356)
c = 18.87
You might be interested in
4.75 miles x 5 = 23.75 / 23 3/4 miles
We can re-create the quadratic equation by (x -3) * (x -2) x^2 -5x + 6 = 0
Answer: The missing term for W is 10.5.
Step-by-step explanation:
W + 9/6 = 12
W +9/6 - 9/6 = 12- 9/6
W = 12 - 1.5
W = 10.5
Answer:
They keep removing my answer but it’s -6
Step-by-step explanation:
286 588 300 :) your welcome